Every engineer keeps a copy of the classic beam tables within reach — reactions, shear, moment, and deflection formulas for the standard support and loading conditions, best known from the American Wood Council's free Design Aid No. 6, "Beam Design Formulas with Shear and Moment Diagrams" (AWC DA6 — Beam Design Formulas with Shear and Moment Diagrams). This page is a worked companion to those tables, with two things the tables themselves can't show:
- One identical beam runs through all 32 cases. Same section, same span, same load intensity — only the supports and load arrangement change. The formulas stop being abstract: you watch Mmax fall from 12,800 lb·ft (cantilever) to 3,200 lb·ft (simple span) to 2,133 lb·ft (fixed ends) for the same 100 plf.
- Every closed-form value is checked against an independent calculation. The tables below print each formula's number next to the same quantity computed by StructSuite's finite-element beam engine (the analysis core of the Wood & Steel Beam module), with the difference. The agreement is locked by an automated test — if either side ever drifts, the build fails.
The drawings, layout, and worked numbers here are our own; the case set and figure numbering follow AWC DA6 so you can cross-reference the original PDF line by line. Formulas are the standard closed-form statics results found in every mechanics text.
#The setup: one beam, 32 conditions — where each input comes from
Why these inputs. None of the numbers below is code-prescribed — this page verifies statics, so the inputs are chosen to be representative and readable, not to design anything: a 16-ft span and 100 plf are ordinary residential floor-beam territory, 1,000 lb is a round concentrated load big enough that its diagrams read clearly, and the 4-ft overhang and quarter-point positions exercise the a/b/c terms of the formulas. The section only supplies EI (deflection scale); any section would verify the same formulas.
The reference beam. A 4x10 Douglas Fir-Larch No. 2 (E = 1.6 × 106 psi, Ix = 230.8 in4, EI = 369 × 106 lb·in2) — a common sawn beam size, used purely as the analysis section. Self-weight is excluded so the closed forms apply exactly.
The standard inputs, identical in every case they appear: span L = 16 ft (each span, for two-span cases), uniform/peak intensity w = 100 plf, concentrated load P = 1,000 lb, overhang a = 4 ft, second span L2 = 12 ft and second load P2 = 500 lb where a case needs unequal values, and concentrated loads at the quarter point (a = 4 ft) for the "any point" cases.
Notation: L = span length (the classic tables write it as script ℓ — same quantity; we use a plain L so it can never be misread next to E and I); a, b, c = position dimensions; w = load per unit length; W = total load; P = concentrated load; R = reaction; V = shear; M = bending moment; Δ = deflection; E = modulus of elasticity; I = moment of inertia; x = distance from the reaction. Formulas evaluate in inches and lb; this page reports M in lb·ft and Δ in inches.
How to read each card: two sketches, then the two diagrams. The general case comes first, labelled purely with the symbols the formulas use — R1/R2 reaction arrows at the supports, P and w on the loads, the a/b/c/L dimensions as drafting dimension lines. Below it, the same case with this page's numbers (1,000 lb, 100 plf, 4 ft…), so symbol and value line up one over the other. Then the shear and moment diagrams as the engine actually computes them (not schematic shapes — jumps, kinks, and sign reversals are the real solution) with the governing values marked by name (Mmax, M1, Vmax…), the case's full formula set, and the comparison table: closed form vs engine, with the difference. Anchors: link to any case as #fig-N.
#Simple beams
One span, a pin and a roller — every other case on this page is a variation on this one. Watch two numbers as the loading changes: Mmax = wL²/8 for the full uniform load (Figure 1) is the yardstick everything else is measured against, and the deflection coefficient collapses fast as load concentrates toward the supports.
#Figure 1 — Simple Beam — Uniformly Distributed Load
This run: L = 16 ft, w = 100 plf
Formula set
- R = V = wL/2
- Vx = w(L/2 − x)
- Mmax (at center) = wL2/8
- Mx = wx(L − x)/2
- Δmax (at center) = 5wL4/384EI
- Δx = wx(L3 − 2Lx2 + x3)/24EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R2 | wL/2 | 800.0 lb | 800.0 lb | 0.00% |
| Vmax | wL/2 | 800.0 lb | 800.0 lb | 0.00% |
| Mmax (at center) | wL2/8 | 3,200.0 lb·ft | 3,200.2 lb·ft | 0.01% |
| Δmax (at center) | 5wL4/384EI | 0.3993 in | 0.3993 in | 0.00% |
#Figure 2 — Simple Beam — Uniform Load Partially Distributed
This run: L = 16 ft, w = 100 plf over the middle b = 8 ft (a = c = 4 ft)
Formula set
- R1 = V1 (max when a < c) = wb(2c + b)/2L
- R2 = V2 (max when a > c) = wb(2a + b)/2L
- Vx (when x > a and < (a + b)) = R1 − w(x − a)
- Mmax (at x = a + R1/w) = R1(a + R1/2w)
- Mx (when x < a) = R1x
- Mx (when x > a and < (a + b)) = R1x − w(x − a)2/2
- Mx (when x > (a + b)) = R2(L − x)
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R2 | wb(2c + b)/2L | 400.0 lb | 400.0 lb | 0.00% |
| Vmax | R1 | 400.0 lb | 400.0 lb | 0.00% |
| Mmax (at x = a + R1/w) | R1(a + R1/2w) | 2,400.0 lb·ft | 2,400.2 lb·ft | 0.01% |
#Figure 3 — Simple Beam — Uniform Load Partially Distributed at One End
This run: L = 16 ft, w = 100 plf over the left a = 8 ft
Formula set
- R1 = V1 = wa(2L − a)/2L
- R2 = V2 = wa2/2L
- Vx (when x < a) = R1 − wx
- Mmax (at x = R1/w) = R12/2w
- Mx (when x < a) = R1x − wx2/2
- Mx (when x > a) = R2(L − x)
- Δx (when x < a) = wx[a2(2L − a)2 − 2ax2(2L − a) + Lx3]/24EIL
- Δx (when x > a) = wa2(L − x)(4xL − 2x2 − a2)/24EIL
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | wa(2L − a)/2L | 600.0 lb | 600.0 lb | 0.00% |
| R2 | wa2/2L | 200.0 lb | 200.0 lb | 0.00% |
| Vmax | R1 | 600.0 lb | 600.0 lb | 0.00% |
| Mmax (at x = R1/w) | R12/2w | 1,800.0 lb·ft | 1,800.2 lb·ft | 0.01% |
#Figure 4 — Simple Beam — Uniform Load Partially Distributed at Each End
This run: L = 16 ft, w1 = w2 = 100 plf over a = c = 4 ft at each end
Formula set
- R1 = V1 = [w1a(2L − a) + w2c2]/2L
- R2 = V2 = [w2c(2L − c) + w1a2]/2L
- Vx (when x < a) = R1 − w1x
- Vx (when x > a and < (a + b)) = R1 − w1a
- Vx (when x > (a + b)) = R2 − w2(L − x)
- Mmax (at x = R1/w1 when R1 < w1a) = R12/2w1
- Mmax (at x = L − R2/w2 when R2 < w2c) = R22/2w2
- Mx (when x < a) = R1x − w1x2/2
- Mx (when x > a and < (a + b)) = R1x − w1a(2x − a)/2
- Mx (when x > (a + b)) = R2(L − x) − w2(L − x)2/2
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R2 | [w1a(2L − a) + w2c2]/2L | 400.0 lb | 400.0 lb | 0.00% |
| Vmax | R1 | 400.0 lb | 400.0 lb | 0.00% |
| Mmax (at x = R1/w1) | R12/2w1 | 800.0 lb·ft | 800.2 lb·ft | 0.03% |
#Figure 5 — Simple Beam — Load Increasing Uniformly to One End
This run: L = 16 ft, 0 → 100 plf (total W = 800 lb, peak at R2)
Formula set
- R1 = V1 = W/3
- R2 = V2 = 2W/3
- Vx = W/3 − Wx2/L2
- Mmax (at x = L/√3 = 0.5774L) = 2WL/9√3 = 0.1283WL
- Mx = Wx(L2 − x2)/3L2
- Δmax (at x = L√(1 − √(8/15)) = 0.5193L) = 0.01304WL3/EI
- Δx = Wx(3x4 − 10L2x2 + 7L4)/180EIL2
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | W/3 | 266.7 lb | 266.7 lb | 0.00% |
| R2 | 2W/3 | 533.3 lb | 533.3 lb | 0.00% |
| Vmax | 2W/3 | 533.3 lb | 533.3 lb | 0.00% |
| Mmax (at 0.5774L) | 0.1283WL | 1,642.2 lb·ft | 1,642.2 lb·ft | 0.00% |
| Δmax (at 0.5193L) | 0.01304WL3/EI | 0.1999 in | 0.2000 in | 0.03% |
#Figure 6 — Simple Beam — Load Increasing Uniformly to Center
This run: L = 16 ft, 0 → 100 plf → 0 (total W = 800 lb, peak at center)
Formula set
- R = V = W/2
- Vx (when x < L/2) = W(L2 − 4x2)/2L2
- Mmax (at center) = WL/6
- Mx (when x < L/2) = Wx(1/2 − 2x2/3L2)
- Δmax (at center) = WL3/60EI
- Δx = Wx(5L2 − 4x2)2/480EIL2
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R2 | W/2 | 400.0 lb | 400.0 lb | 0.00% |
| Vmax | W/2 | 400.0 lb | 400.0 lb | 0.00% |
| Mmax (at center) | WL/6 | 2,133.3 lb·ft | 2,133.6 lb·ft | 0.01% |
| Δmax (at center) | WL3/60EI | 0.2556 in | 0.2556 in | 0.00% |
#Figure 7 — Simple Beam — Concentrated Load at Center
This run: L = 16 ft, P = 1,000 lb at midspan
Formula set
- R = V = P/2
- Mmax (at point of load) = PL/4
- Mx (when x < L/2) = Px/2
- Δmax (at point of load) = PL3/48EI
- Δx (when x < L/2) = Px(3L2 − 4x2)/48EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R2 | P/2 | 500.0 lb | 500.0 lb | 0.00% |
| Vmax | P/2 | 500.0 lb | 500.0 lb | 0.00% |
| Mmax (at center) | PL/4 | 4,000.0 lb·ft | 4,000.0 lb·ft | 0.00% |
| Δmax (at center) | PL3/48EI | 0.3993 in | 0.3993 in | 0.00% |
#Figure 8 — Simple Beam — Concentrated Load at Any Point
This run: L = 16 ft, P = 1,000 lb at a = 4 ft (b = 12 ft)
Formula set
- R1 = V1 (max when a < b) = Pb/L
- R2 = V2 (max when a > b) = Pa/L
- Mmax (at point of load) = Pab/L
- Mx (when x < a) = Pbx/L
- Δmax (at x = √(a(a + 2b)/3) when a > b) = Pab(a + 2b)√(3a(a + 2b))/27EIL
- Δa (at point of load) = Pa2b2/3EIL
- Δx (when x < a) = Pbx(L2 − b2 − x2)/6EIL
- Δx (when x > a) = Pa(L − x)(2Lx − x2 − a2)/6EIL
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | Pb/L | 750.0 lb | 750.0 lb | 0.00% |
| R2 | Pa/L | 250.0 lb | 250.0 lb | 0.00% |
| Vmax | Pb/L | 750.0 lb | 750.0 lb | 0.00% |
| Mmax (at point of load) | Pab/L | 3,000.0 lb·ft | 3,000.0 lb·ft | 0.00% |
| Δmax | Pab(a + 2b)√(3a(a + 2b))/27EIL | 0.2790 in | 0.2790 in | 0.00% |
#Figure 9 — Simple Beam — Two Equal Concentrated Loads Symmetrically Placed
This run: L = 16 ft, P = 1,000 lb each at a = 4 ft from each end
Formula set
- R = V = P
- Mmax (between loads) = Pa
- Mx (when x < a) = Px
- Δmax (at center) = Pa(3L2 − 4a2)/24EI
- Δx (when x < a) = Px(3La − 3a2 − x2)/6EI
- Δx (when x > a and < (L − a)) = Pa(3Lx − 3x2 − a2)/6EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R2 | P | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Vmax | P | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Mmax (between loads) | Pa | 4,000.0 lb·ft | 4,000.0 lb·ft | 0.00% |
| Δmax (at center) | Pa(3L2 − 4a2)/24EI | 0.5490 in | 0.5490 in | 0.00% |
#Figure 10 — Simple Beam — Two Equal Concentrated Loads Unsymmetrically Placed
This run: L = 16 ft, P = 1,000 lb each at a = 4 ft from the left and b = 6 ft from the right
Formula set
- R1 = V1 (max when a < b) = P(L − a + b)/L
- R2 = V2 (max when a > b) = P(L − b + a)/L
- Vx (when x > a and < (L − b)) = P(b − a)/L
- M1 (max when a > b) = R1a
- M2 (max when a < b) = R2b
- Mx (when x < a) = R1x
- Mx (when x > a and < (L − b)) = R1x − P(x − a)
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | P(L − a + b)/L | 1,125.0 lb | 1,125.0 lb | 0.00% |
| R2 | P(L − b + a)/L | 875.0 lb | 875.0 lb | 0.00% |
| Vmax | R1 | 1,125.0 lb | 1,125.0 lb | 0.00% |
| M2 (at the second load) | R2b | 5,250.0 lb·ft | 5,250.0 lb·ft | 0.00% |
#Figure 11 — Simple Beam — Two Unequal Concentrated Loads Unsymmetrically Placed
This run: L = 16 ft, P1 = 1,000 lb at a = 4 ft, P2 = 500 lb at b = 6 ft from the right
Formula set
- R1 = V1 = [P1(L − a) + P2b]/L
- R2 = V2 = [P1a + P2(L − b)]/L
- Vx (when x > a and < (L − b)) = R1 − P1
- M1 (max when R1 < P1) = R1a
- M2 (max when R2 < P2) = R2b
- Mx (when x < a) = R1x
- Mx (when x > a and < (L − b)) = R1x − P1(x − a)
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | [P1(L − a) + P2b]/L | 937.5 lb | 937.5 lb | 0.00% |
| R2 | [P1a + P2(L − b)]/L | 562.5 lb | 562.5 lb | 0.00% |
| Vmax | R1 | 937.5 lb | 937.5 lb | 0.00% |
| M1 (at P1) | R1a | 3,750.0 lb·ft | 3,750.0 lb·ft | 0.00% |
#Cantilever beams
Fix one end, free the other. The moment arm doubles and the coefficient jumps from wL²/8 to wL²/2 — four times the simple-span moment for the same load — and deflection grows almost an order of magnitude. This is why the same section that works fine on a simple span is rarely adequate as a full-length cantilever.
#Figure 12 — Cantilever Beam — Uniformly Distributed Load
This run: L = 16 ft, w = 100 plf, fixed at the right end
Formula set
- R = V = wL
- Vx = wx (x from the free end)
- Mmax (at fixed end) = wL2/2
- Mx = wx2/2
- Δmax (at free end) = wL4/8EI
- Δx = w(x4 − 4L3x + 3L4)/24EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R | wL | 1,600.0 lb | 1,600.0 lb | 0.00% |
| Vmax | wL | 1,600.0 lb | 1,600.0 lb | 0.00% |
| Mmax (at fixed end) | wL2/2 | 12,800.0 lb·ft | 12,799.8 lb·ft | 0.00% |
| Δmax (at free end) | wL4/8EI | 3.8333 in | 3.8333 in | 0.00% |
#Figure 13 — Cantilever Beam — Concentrated Load at Free End
This run: L = 16 ft, P = 1,000 lb at the free end, fixed at the right end
Formula set
- R = V = P
- Mmax (at fixed end) = PL
- Mx = Px (x from the free end)
- Δmax (at free end) = PL3/3EI
- Δx = P(2L3 − 3L2x + x3)/6EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R | P | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Vmax | P | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Mmax (at fixed end) | PL | 16,000.0 lb·ft | 16,000.0 lb·ft | 0.00% |
| Δmax (at free end) | PL3/3EI | 6.3889 in | 6.3889 in | 0.00% |
#Figure 14 — Cantilever Beam — Concentrated Load at Any Point
This run: L = 16 ft, P = 1,000 lb at a = 4 ft from the free end (b = 12 ft to the fixed end)
Formula set
- R = V = P
- Mmax (at fixed end) = Pb
- Mx (when x > a) = P(x − a) (x from the free end)
- Δmax (at free end) = Pb2(3L − b)/6EI
- Δa (at point of load) = Pb3/3EI
- Δx (when x < a) = Pb2(3L − 3x − b)/6EI
- Δx (when x > a) = P(L − x)2(3b − L + x)/6EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R | P | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Vmax | P | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Mmax (at fixed end) | Pb | 12,000.0 lb·ft | 12,000.0 lb·ft | 0.00% |
| Δmax (at free end) | Pb2(3L − b)/6EI | 4.0430 in | 4.0430 in | 0.00% |
#Propped cantilevers (fixed at one end, supported at the other)
Adding a simple support to a cantilever (or fixing one end of a simple beam) makes the beam statically indeterminate: the fixed end picks up 5/8 of a uniform load, the moment splits into a hogging peak at the wall (wL²/8) and a smaller sagging peak (9wL²/128), and deflection drops to less than half the simple span’s.
#Figure 15 — Beam Fixed at One End, Supported at Other — Uniformly Distributed Load
This run: L = 16 ft, w = 100 plf, simple support left (R1), fixed right (R2)
Formula set
- R1 = V1 = 3wL/8
- R2 = V2 = 5wL/8
- Vx = R1 − wx
- Mmax (at fixed end) = wL2/8
- M1 (at x = 3L/8) = 9wL2/128
- Mx = R1x − wx2/2
- Δmax (at x = (L/16)(1 + √33) = 0.4215L) = wL4/185EI
- Δx = wx(L3 − 3Lx2 + 2x3)/48EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 (simple end) | 3wL/8 | 600.0 lb | 600.0 lb | 0.00% |
| R2 (fixed end) | 5wL/8 | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Vmax | 5wL/8 | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Mmax (at fixed end) | wL2/8 | 3,200.0 lb·ft | 3,199.8 lb·ft | 0.01% |
| M1 (at 3L/8) | 9wL2/128 | 1,800.0 lb·ft | 1,800.2 lb·ft | 0.01% |
| Δmax (at 0.4215L) | wL4/185EI | 0.1658 in | 0.1661 in | 0.20% |
#Figure 16 — Beam Fixed at One End, Supported at Other — Concentrated Load at Center
This run: L = 16 ft, P = 1,000 lb at midspan, simple left, fixed right
Formula set
- R1 = V1 = 5P/16
- R2 = V2 = 11P/16
- Mmax (at fixed end) = 3PL/16
- M1 (at point of load) = 5PL/32
- Mx (when x < L/2) = 5Px/16
- Mx (when x > L/2) = P(L/2 − 11x/16)
- Δmax (at x = L√(1/5) = 0.4472L) = PL3/48EI√5 = 0.009317PL3/EI
- Δx (at point of load) = 7PL3/768EI
- Δx (when x < L/2) = Px(3L2 − 5x2)/96EI
- Δx (when x > L/2) = P(x − L)2(11x − 2L)/96EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 (simple end) | 5P/16 | 312.5 lb | 312.5 lb | 0.00% |
| R2 (fixed end) | 11P/16 | 687.5 lb | 687.5 lb | 0.00% |
| Vmax | 11P/16 | 687.5 lb | 687.5 lb | 0.00% |
| Mmax (at fixed end) | 3PL/16 | 3,000.0 lb·ft | 3,000.0 lb·ft | 0.00% |
| M1 (at point of load) | 5PL/32 | 2,500.0 lb·ft | 2,500.0 lb·ft | 0.00% |
| Δmax (at 0.4472L) | 0.009317PL3/EI | 0.1786 in | 0.1786 in | 0.00% |
#Figure 17 — Beam Fixed at One End, Supported at Other — Concentrated Load at Any Point
This run: L = 16 ft, P = 1,000 lb at a = 4 ft from the simple support (b = 12 ft)
Formula set
- R1 = V1 = Pb2(a + 2L)/2L3
- R2 = V2 = Pa(3L2 − a2)/2L3
- M1 (at point of load) = R1a
- M2 (at fixed end) = Pab(a + L)/2L2
- Mx (when x < a) = R1x
- Mx (when x > a) = R1x − P(x − a)
- Δmax (when a < 0.414L, at x = L(L2 + a2)/(3L2 − a2)) = Pa(L2 − a2)3/3EI(3L2 − a2)2
- Δmax (when a > 0.414L, at x = L√(a/(2L + a))) = Pab2√(a/(2L + a))/6EI
- Δa (at point of load) = Pa2b3(3L + a)/12EIL3
- Δx (when x < a) = Pb2x(3aL2 − 2Lx2 − ax2)/12EIL3
- Δx (when x > a) = Pa(L − x)2(3L2x − a2x − 2a2L)/12EIL3
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 (simple end) | Pb2(a + 2L)/2L3 | 632.8 lb | 632.8 lb | 0.00% |
| R2 (fixed end) | Pa(3L2 − a2)/2L3 | 367.2 lb | 367.2 lb | 0.00% |
| Vmax | R1 | 632.8 lb | 632.8 lb | 0.00% |
| M1 (at point of load) | R1a | 2,531.3 lb·ft | 2,531.3 lb·ft | 0.00% |
| M2 (at fixed end) | Pab(a + L)/2L2 | 1,875.0 lb·ft | 1,875.0 lb·ft | 0.00% |
| Δmax | Pa(L2 − a2)3/3EI(3L2 − a2)2 | 0.1525 in | 0.1525 in | 0.00% |
#Overhanging beams
Push the beam past its support and the hogging moment over that support (wa²/2 or Pa) fights the sagging moment between supports. A short overhang barely dents the span moment; load only the overhang and the far reaction goes negative — the beam tries to lift off its first support.
#Figure 18 — Beam Overhanging One Support — Uniformly Distributed Load
This run: L = 16 ft between supports, a = 4 ft overhang, w = 100 plf over the whole length
Formula set
- R1 = V1 = w(L2 − a2)/2L
- R2 = V2 + V3 = w(L + a)2/2L
- V2 = wa
- V3 = w(L2 + a2)/2L
- Vx (between supports) = R1 − wx
- Vx1 (for overhang) = w(a − x1)
- M1 (at x = (L/2)(1 − a2/L2)) = w(L + a)2(L − a)2/8L2
- M2 (at R2) = wa2/2
- Mx (between supports) = wx(L2 − a2 − xL)/2L
- Mx1 (for overhang) = w(a − x1)2/2
- Δx (between supports) = wx(L4 − 2L2x2 + Lx3 − 2a2L2 + 2a2x2)/24EIL
- Δx1 (for overhang) = wx1(4a2L − L3 + 6a2x1 − 4ax12 + x13)/24EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | w(L2 − a2)/2L | 750.0 lb | 750.0 lb | 0.00% |
| R2 | w(L + a)2/2L | 1,250.0 lb | 1,250.0 lb | 0.00% |
| Vmax | V3 = w(L2 + a2)/2L | 850.0 lb | 850.0 lb | 0.00% |
| M1 (between supports) | w(L + a)2(L − a)2/8L2 | 2,812.5 lb·ft | 2,812.7 lb·ft | 0.01% |
| M2 (at R2) | wa2/2 | 800.0 lb·ft | 799.8 lb·ft | 0.03% |
#Figure 19 — Beam Overhanging One Support — Uniformly Distributed Load on Overhang
This run: L = 16 ft between supports, a = 4 ft overhang, w = 100 plf on the overhang only
Formula set
- R1 = V1 = wa2/2L (downward)
- R2 = V1 + V2 = wa(2L + a)/2L
- V2 = wa
- Vx1 (for overhang) = w(a − x1)
- Mmax (at R2) = wa2/2
- Mx (between supports) = wa2x/2L
- Mx1 (for overhang) = w(a − x1)2/2
- Δmax (between supports, at x = L/√3) = wa2L2/18√3EI = 0.03208wa2L2/EI
- Δmax (for overhang, at x1 = a) = wa3(4L + 3a)/24EI
- Δx (between supports) = wa2x(L2 − x2)/12EIL
- Δx1 (for overhang) = wx1(4a2L + 6a2x1 − 4ax12 + x13)/24EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | −wa2/2L | -50.0 lb | -50.0 lb | 0.00% |
| R2 | wa(2L + a)/2L | 450.0 lb | 450.0 lb | 0.00% |
| Vmax | V2 = wa | 400.0 lb | 400.0 lb | 0.00% |
| Mmax (at R2) | wa2/2 | 800.0 lb·ft | 800.0 lb·ft | 0.00% |
| Δmax (between supports) | 0.03208wa2L2/EI | 0.0615 in | 0.0615 in | 0.02% |
| Δmax (overhang tip) | wa3(4L + 3a)/24EI | 0.0948 in | 0.0948 in | 0.00% |
#Figure 20 — Beam Overhanging One Support — Concentrated Load at End of Overhang
This run: L = 16 ft between supports, a = 4 ft overhang, P = 1,000 lb at the tip
Formula set
- R1 = V1 = Pa/L (downward)
- R2 = V1 + V2 = P(L + a)/L
- V2 = P
- Mmax (at R2) = Pa
- Mx (between supports) = Pax/L
- Mx1 (for overhang) = P(a − x1)
- Δmax (between supports, at x = L/√3) = PaL2/9√3EI = 0.06415PaL2/EI
- Δmax (for overhang, at x1 = a) = Pa2(L + a)/3EI
- Δx (between supports) = Pax(L2 − x2)/6EIL
- Δx1 (for overhang) = Px1(2aL + 3ax1 − x12)/6EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | −Pa/L | -250.0 lb | -250.0 lb | 0.00% |
| R2 | P(L + a)/L | 1,250.0 lb | 1,250.0 lb | 0.00% |
| Vmax | V2 = P | 1,000.0 lb | 1,000.0 lb | 0.00% |
| Mmax (at R2) | Pa | 4,000.0 lb·ft | 4,000.0 lb·ft | 0.00% |
| Δmax (between supports) | 0.06415PaL2/EI | 0.3074 in | 0.3074 in | 0.00% |
| Δmax (overhang tip) | Pa2(L + a)/3EI | 0.4991 in | 0.4991 in | 0.00% |
#Figure 21 — Beam Overhanging One Support — Concentrated Load at Any Point Between Supports
This run: L = 16 ft between supports, a = 4 ft overhang, P = 1,000 lb at a = 4 ft from R1
Formula set
- R1 = V1 (max when a < b) = Pb/L
- R2 = V2 (max when a > b) = Pa/L
- Mmax (at point of load) = Pab/L
- Mx (when x < a) = Pbx/L
- Δmax (at x = √(a(a + 2b)/3) when a > b) = Pab(a + 2b)√(3a(a + 2b))/27EIL
- Δa (at point of load) = Pa2b2/3EIL
- Δx (when x < a) = Pbx(L2 − b2 − x2)/6EIL
- Δx (when x > a) = Pa(L − x)(2Lx − x2 − a2)/6EIL
- Δx1 (for overhang) = Pabx1(L + a)/6EIL
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | Pb/L | 750.0 lb | 750.0 lb | 0.00% |
| R2 | Pa/L | 250.0 lb | 250.0 lb | 0.00% |
| Vmax | Pb/L | 750.0 lb | 750.0 lb | 0.00% |
| Mmax (at point of load) | Pab/L | 3,000.0 lb·ft | 3,000.0 lb·ft | 0.00% |
| Δmax (between supports) | Pab(a + 2b)√(3a(a + 2b))/27EIL | 0.2790 in | 0.2790 in | 0.00% |
| Δ (overhang tip, x1 = a) | Pabx1(L + a)/6EIL | 0.1872 in | 0.1872 in | 0.00% |
#Figure 22 — Beam Overhanging Both Supports — Unequal Overhangs — Uniformly Distributed Load
This run: span b = 16 ft, overhangs a = 4 ft and c = 2 ft (total L = 22 ft), w = 100 plf over the whole length
Formula set
- R1 = wL(L − 2c)/2b
- R2 = wL(L − 2a)/2b
- V1 = wa; V2 = R1 − V1; V3 = R2 − V4; V4 = wc
- Vx1 = V1 − wx1
- Vx (when x < L) = R1 − w(a + x)
- Vm (when a < c) = R2 − wc
- M1 = −wa2/2
- M2 = −wc2/2
- M3 = R1(R1/2w − a)
- Mx (max when x = R1/w − a) = R1x − w(a + x)2/2
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | wL(L − 2c)/2b | 1,237.5 lb | 1,237.5 lb | 0.00% |
| R2 | wL(L − 2a)/2b | 962.5 lb | 962.5 lb | 0.00% |
| Vmax | V2 = R1 − wa | 837.5 lb | 837.5 lb | 0.00% |
| M3 (between supports) | R1(R1/2w − a) | 2,707.0 lb·ft | 2,707.2 lb·ft | 0.01% |
| M1 (at R1) | wa2/2 | 800.0 lb·ft | 799.8 lb·ft | 0.03% |
#Fixed-fixed beams
Full end restraint is the stiffest condition here: the uniform-load moment drops to wL²/12 at the walls (and wL²/24 at midspan), and deflection is a fifth of the simple span’s. The price is real end moments the connections must actually develop — which is why true fixity is rare in wood construction.
#Figure 23 — Beam Fixed at Both Ends — Uniformly Distributed Load
This run: L = 16 ft, w = 100 plf
Formula set
- R = V = wL/2
- Vx = w(L/2 − x)
- Mmax (at ends) = wL2/12
- M1 (at center) = wL2/24
- Mx = w(6Lx − L2 − 6x2)/12
- Δmax (at center) = wL4/384EI
- Δx = wx2(L − x)2/24EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R2 | wL/2 | 800.0 lb | 800.0 lb | 0.00% |
| Vmax | wL/2 | 800.0 lb | 800.0 lb | 0.00% |
| Mmax (at ends) | wL2/12 | 2,133.3 lb·ft | 2,133.1 lb·ft | 0.01% |
| M1 (at center) | wL2/24 | 1,066.7 lb·ft | 1,066.9 lb·ft | 0.02% |
| Δmax (at center) | wL4/384EI | 0.0799 in | 0.0799 in | 0.00% |
#Figure 24 — Beam Fixed at Both Ends — Concentrated Load at Center
This run: L = 16 ft, P = 1,000 lb at midspan
Formula set
- R = V = P/2
- Mmax (at center and ends) = PL/8
- Mx (when x < L/2) = P(4x − L)/8
- Δmax (at center) = PL3/192EI
- Δx (when x < L/2) = Px2(3L − 4x)/48EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R2 | P/2 | 500.0 lb | 500.0 lb | 0.00% |
| Vmax | P/2 | 500.0 lb | 500.0 lb | 0.00% |
| Mmax (at center) | PL/8 | 2,000.0 lb·ft | 2,000.0 lb·ft | 0.00% |
| Mmax (at ends) | PL/8 | 2,000.0 lb·ft | 2,000.0 lb·ft | 0.00% |
| Δmax (at center) | PL3/192EI | 0.0998 in | 0.0998 in | 0.00% |
#Figure 25 — Beam Fixed at Both Ends — Concentrated Load at Any Point
This run: L = 16 ft, P = 1,000 lb at a = 4 ft (b = 12 ft)
Formula set
- R1 = V1 (max when a < b) = Pb2(3a + b)/L3
- R2 = V2 (max when a > b) = Pa2(a + 3b)/L3
- M1 (max when a < b) = Pab2/L2
- M2 (max when a > b) = Pa2b/L2
- Ma (at point of load) = 2Pa2b2/L3
- Mx (when x < a) = R1x − Pab2/L2
- Δmax (when a > b, at x = 2aL/(3a + b)) = 2Pa3b2/3EI(3a + b)2
- Δa (at point of load) = Pa3b3/3EIL3
- Δx (when x < a) = Pb2x2(3aL − 3ax − bx)/6EIL3
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | Pb2(3a + b)/L3 | 843.8 lb | 843.7 lb | 0.00% |
| R2 | Pa2(a + 3b)/L3 | 156.3 lb | 156.2 lb | 0.00% |
| Vmax | R1 | 843.8 lb | 843.8 lb | 0.00% |
| M1 (at the near fixed end) | Pab2/L2 | 2,250.0 lb·ft | 2,250.0 lb·ft | 0.00% |
| Ma (at point of load) | 2Pa2b2/L3 | 1,125.0 lb·ft | 1,125.0 lb·ft | 0.00% |
| Δmax | 2Pa3b2/3EI(3a + b)2 | 0.0539 in | 0.0539 in | 0.00% |
#Two-span continuous beams
Continuity trades midspan moment for a hogging peak over the center support (wL²/8 for both spans loaded) and an uplift surprise: load ONE span and the far-end reaction goes negative. The center support collects 10/8 of wL — the reaction the post and footing below must be designed for.
#Figure 26 — Continuous Beam — Two Equal Spans — Uniform Load on One Span
This run: two 16-ft spans, w = 100 plf on the first span only
Formula set
- R1 = V1 = 7wL/16
- R2 = V2 + V3 = 5wL/8
- R3 = V3 = −wL/16
- V2 = 9wL/16
- Mmax (at x = 7L/16) = 49wL2/512
- M1 (at support R2) = wL2/16
- Mx (when x < L) = wx(7L − 8x)/16
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | 7wL/16 | 700.0 lb | 700.0 lb | 0.00% |
| R2 | 5wL/8 | 1,000.0 lb | 1,000.0 lb | 0.00% |
| R3 | −wL/16 | -100.0 lb | -100.0 lb | 0.00% |
| Vmax | V2 = 9wL/16 | 900.0 lb | 900.0 lb | 0.00% |
| Mmax (at 7L/16) | 49wL2/512 | 2,450.0 lb·ft | 2,450.2 lb·ft | 0.01% |
| M1 (at R2) | wL2/16 | 1,600.0 lb·ft | 1,600.0 lb·ft | 0.00% |
#Figure 27 — Continuous Beam — Two Equal Spans — Concentrated Load at Center of One Span
This run: two 16-ft spans, P = 1,000 lb at the center of the first span
Formula set
- R1 = V1 = 13P/32
- R2 = V2 + V3 = 11P/16
- R3 = V3 = −3P/32
- V2 = 19P/32
- Mmax (at point of load) = 13PL/64
- M1 (at support R2) = 3PL/32
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | 13P/32 | 406.3 lb | 406.3 lb | 0.00% |
| R2 | 11P/16 | 687.5 lb | 687.5 lb | 0.00% |
| R3 | −3P/32 | -93.8 lb | -93.8 lb | 0.00% |
| Vmax | V2 = 19P/32 | 593.8 lb | 593.8 lb | 0.00% |
| Mmax (at point of load) | 13PL/64 | 3,250.0 lb·ft | 3,250.0 lb·ft | 0.00% |
| M1 (at R2) | 3PL/32 | 1,500.0 lb·ft | 1,500.0 lb·ft | 0.00% |
#Figure 28 — Continuous Beam — Two Equal Spans — Concentrated Load at Any Point
This run: two 16-ft spans, P = 1,000 lb at a = 4 ft into the first span (b = 12 ft)
Formula set
- R1 = V1 = Pb[4L2 − a(L + a)]/4L3
- R2 = V2 + V3 = Pa[2L2 + b(L + a)]/2L3
- R3 = V3 = −Pab(L + a)/4L3
- V2 = Pa[4L2 + b(L + a)]/4L3
- Mmax (at point of load) = Pb[4L2 − a(L + a)]a/4L3
- M1 (at support R2) = Pab(L + a)/4L2
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | Pb[4L2 − a(L + a)]/4L3 | 691.4 lb | 691.4 lb | 0.00% |
| R2 | Pa[2L2 + b(L + a)]/2L3 | 367.2 lb | 367.2 lb | 0.00% |
| R3 | −Pab(L + a)/4L3 | -58.6 lb | -58.6 lb | 0.00% |
| Vmax | R1 | 691.4 lb | 691.4 lb | 0.00% |
| Mmax (at point of load) | R1a | 2,765.6 lb·ft | 2,765.6 lb·ft | 0.00% |
| M1 (at R2) | Pab(L + a)/4L2 | 937.5 lb·ft | 937.5 lb·ft | 0.00% |
#Figure 29 — Continuous Beam — Two Equal Spans — Uniformly Distributed Load
This run: two 16-ft spans, w = 100 plf on both spans
Formula set
- R1 = V1 = R3 = V3 = 3wL/8
- R2 = 10wL/8
- V2 = Vmax = 5wL/8
- M1 (at support R2) = wL2/8
- M2 (at 3L/8) = 9wL2/128
- Δmax (at 0.4215L from R1 and R3) = wL4/185EI
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R3 | 3wL/8 | 600.0 lb | 600.0 lb | 0.00% |
| R2 | 10wL/8 | 2,000.0 lb | 2,000.0 lb | 0.00% |
| Vmax | 5wL/8 | 1,000.0 lb | 1,000.0 lb | 0.00% |
| M1 (at R2) | wL2/8 | 3,200.0 lb·ft | 3,199.8 lb·ft | 0.01% |
| M2 (at 3L/8) | 9wL2/128 | 1,800.0 lb·ft | 1,800.2 lb·ft | 0.01% |
| Δmax (at 0.4215L) | wL4/185EI | 0.1658 in | 0.1661 in | 0.20% |
#Figure 30 — Continuous Beam — Two Equal Spans — Two Equal Concentrated Loads Symmetrically Placed
This run: two 16-ft spans, P = 1,000 lb at the center of each span (a = L/2)
Formula set
- R1 = V1 = R3 = V3 = 5P/16
- R2 = 2V2 = 11P/8
- V2 = P − R1 = 11P/16
- Vmax = V2
- M1 = −3PL/16
- M2 = 5PL/32
- Mx (when x < a) = R1x
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 = R3 | 5P/16 | 312.5 lb | 312.5 lb | 0.00% |
| R2 | 11P/8 | 1,375.0 lb | 1,375.0 lb | 0.00% |
| Vmax | 11P/16 | 687.5 lb | 687.5 lb | 0.00% |
| M1 (at R2) | 3PL/16 | 3,000.0 lb·ft | 3,000.0 lb·ft | 0.00% |
| M2 (at loads) | 5PL/32 | 2,500.0 lb·ft | 2,500.0 lb·ft | 0.00% |
#Figure 31 — Continuous Beam — Two Unequal Spans — Uniformly Distributed Load
This run: spans L1 = 16 ft and L2 = 12 ft, w = 100 plf on both
Formula set
- M1 = −(wL23 + wL13)/8(L1 + L2)
- R1 = V1 = M1/L1 + wL1/2
- R2 = wL1 + wL2 − R1 − R3
- R3 = V4 = M1/L2 + wL2/2
- V2 = wL1 − R1; V3 = wL2 − R3
- Mx1 (at x1 = R1/w) = R1x1 − wx12/2
- Mx2 (at x2 = R3/w) = R3x2 − wx22/2
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | M1/L1 + wL1/2 | 637.5 lb | 637.5 lb | 0.00% |
| R2 | wL1 + wL2 − R1 − R3 | 1,779.2 lb | 1,779.2 lb | 0.00% |
| R3 | M1/L2 + wL2/2 | 383.3 lb | 383.3 lb | 0.00% |
| Vmax | V2 = wL1 − R1 | 962.5 lb | 962.5 lb | 0.00% |
| M1 (at R2) | (wL23 + wL13)/8(L1 + L2) | 2,600.0 lb·ft | 2,599.8 lb·ft | 0.01% |
| Mx1 (in span 1) | R1x1 − wx12/2 | 2,032.0 lb·ft | 2,032.2 lb·ft | 0.01% |
#Figure 32 — Continuous Beam — Two Unequal Spans — Concentrated Load on Each Span Symmetrically Placed
This run: spans L1 = 16 ft and L2 = 12 ft, P1 = P2 = 1,000 lb at each span center
Formula set
- M1 = −(3/16)·(P1L12 + P2L22)/(L1 + L2)
- R1 = M1/L1 + P1/2
- R2 = P1 + P2 − R1 − R3
- R3 = M1/L2 + P2/2
- V1 = R1; V2 = P1 − R1; V3 = P2 − R3; V4 = R3
- Mm1 (at P1) = R1a
- Mm2 (at P2) = R3b
| Quantity | Governing formula | Closed form | StructSuite engine | Diff |
|---|---|---|---|---|
| R1 | M1/L1 + P1/2 | 332.6 lb | 332.6 lb | 0.00% |
| R2 | P1 + P2 − R1 − R3 | 1,390.6 lb | 1,390.6 lb | 0.00% |
| R3 | M1/L2 + P2/2 | 276.8 lb | 276.8 lb | 0.00% |
| Vmax | V3 = P2 − R3 | 723.2 lb | 723.2 lb | 0.00% |
| M1 (at R2) | (3/16)(P1L12 + P2L22)/(L1 + L2) | 2,678.6 lb·ft | 2,678.6 lb·ft | 0.00% |
| Mm1 (at P1) | R1a | 2,660.7 lb·ft | 2,660.7 lb·ft | 0.00% |
#Summary of results — one beam, every condition
All values below are the engine's, for the identical inputs above (Δmax is the largest deflection anywhere on the member, overhang tips included).
| Fig. | Case | M⁺max (lb·ft) | M⁻max (lb·ft) | Vmax (lb) | Δmax (in) |
|---|---|---|---|---|---|
| Simple beams | |||||
| 1 | Uniformly Distributed Load | 3,200 | — | 800 | 0.399 |
| 2 | Uniform Load Partially Distributed | 2,400 | — | 400 | 0.285 |
| 3 | Uniform Load Partially Distributed at One End | 1,800 | — | 600 | 0.201 |
| 4 | Uniform Load Partially Distributed at Each End | 800 | — | 400 | 0.115 |
| 5 | Load Increasing Uniformly to One End | 1,642 | — | 533 | 0.200 |
| 6 | Load Increasing Uniformly to Center | 2,134 | — | 400 | 0.256 |
| 7 | Concentrated Load at Center | 4,000 | — | 500 | 0.399 |
| 8 | Concentrated Load at Any Point | 3,000 | — | 750 | 0.279 |
| 9 | Two Equal Concentrated Loads Symmetrically Placed | 4,000 | — | 1,000 | 0.549 |
| 10 | Two Equal Concentrated Loads Unsymmetrically Placed | 5,250 | — | 1,125 | 0.640 |
| 11 | Two Unequal Concentrated Loads Unsymmetrically Placed | 3,750 | — | 938 | 0.458 |
| Cantilever beams | |||||
| 12 | Uniformly Distributed Load | — | 12,800 | 1,600 | 3.833 |
| 13 | Concentrated Load at Free End | — | 16,000 | 1,000 | 6.389 |
| 14 | Concentrated Load at Any Point | — | 12,000 | 1,000 | 4.043 |
| Propped cantilevers (fixed at one end, supported at the other) | |||||
| 15 | Uniformly Distributed Load | 1,800 | 3,200 | 1,000 | 0.166 |
| 16 | Concentrated Load at Center | 2,500 | 3,000 | 688 | 0.179 |
| 17 | Concentrated Load at Any Point | 2,531 | 1,875 | 633 | 0.153 |
| Overhanging beams | |||||
| 18 | Uniformly Distributed Load | 2,813 | 800 | 850 | 0.340 |
| 19 | Uniformly Distributed Load on Overhang | — | 800 | 400 | 0.095 |
| 20 | Concentrated Load at End of Overhang | — | 4,000 | 1,000 | 0.499 |
| 21 | Concentrated Load at Any Point Between Supports | 3,000 | — | 750 | 0.279 |
| 22 | Uniformly Distributed Load | 2,707 | 800 | 838 | 0.325 |
| Fixed-fixed beams | |||||
| 23 | Uniformly Distributed Load | 1,067 | 2,133 | 800 | 0.080 |
| 24 | Concentrated Load at Center | 2,000 | 2,000 | 500 | 0.100 |
| 25 | Concentrated Load at Any Point | 1,125 | 2,250 | 844 | 0.054 |
| Two-span continuous beams | |||||
| 26 | Uniform Load on One Span | 2,450 | 1,600 | 900 | 0.281 |
| 27 | Concentrated Load at Center of One Span | 3,250 | 1,500 | 594 | 0.288 |
| 28 | Concentrated Load at Any Point | 2,766 | 938 | 691 | 0.214 |
| 29 | Uniformly Distributed Load | 1,800 | 3,200 | 1,000 | 0.166 |
| 30 | Two Equal Concentrated Loads Symmetrically Placed | 2,500 | 3,000 | 688 | 0.179 |
| 31 | Uniformly Distributed Load | 2,032 | 2,600 | 962 | 0.208 |
| 32 | Concentrated Load on Each Span Symmetrically Placed | 2,661 | 2,679 | 723 | 0.202 |
Four comparisons worth internalizing:
- Support conditions are worth more than section size. The same 100 plf produces Mmax = 12,800 lb·ft as a cantilever, 3,200 lb·ft simply supported, and 2,133 lb·ft with both ends fixed — a 6.0:1 spread with identical load and length. No practical section upgrade moves capacity that far.
- Deflection is even more dramatic. Under the uniform load the cantilever moves 3.83 in where the simple span moves 0.40 in and the fixed-fixed beam only 0.080 in — a 48× range. For the midspan point load the cantilever-to-simple ratio is 16× (6.39 in vs 0.399 in).
- Continuity concentrates load on the middle support. With both 16-ft spans loaded, the center support carries R2 = 2,000 lb — 10/8 of wL, and 25% more than the 1,600-lb total a simple span would deliver to EACH of two separate posts. The post, plate crushing, and footing under R2 are designed by this number, not by wL/2.
- Partial loading can pull a support DOWN. Load only one span of a continuous beam (Figure 26) and the far reaction is R3 = -100 lb — negative. The same happens loading only an overhang (Figure 19). Pattern loading isn't an academic refinement; it changes the sign of real connections.
#Practical pitfalls when using these formulas
- Units eat more designs than statics does. The deflection formulas want consistent units: with w in lb/in, L in inches, E in psi and I in in4, Δ comes out in inches. Feed L in feet into wL⁴/8EI and the answer is off by 12⁴ ≈ 21,000×. This page evaluates everything in inches and pounds, then reports M in lb·ft — do the same, in one direction, once.
- Superposition is legal only while everything stays linear-elastic on the SAME structure. You may add Figure 1 + Figure 7 on the same simple span; you may not add a simple-span case to a fixed-end case, and you may not superpose onto a beam whose supports have changed (a prop added later is a different structure).
- "Fixed" in the table means a real moment connection. A stud wall top plate or a couple of toe-nails is a pin, whatever the framing looks like. Use the fixed-end cases (Figures 27–32) only where the detail can actually develop M = wL²/12 — in wood construction that is rare enough to treat as the exception.
- Pattern loading changes signs, not just magnitudes. Loading one span of the two-span beam (Figure 26) turns the far reaction NEGATIVE — a connection you sized for bearing now needs a tie-down. Any time a formula's reaction can go negative under partial load, detail for it.
- The maximum is not always where you expect. For a load at "any point" (Figure 8), Mmax is under the load, not midspan; the deflection maximum sits at x = √(a(a + 2b)/3) (a > b) — near, but never at, the load. Read each formula's "at x = …" qualifier before you chase a midspan number.
- These are analysis values, not designs. Nothing here contains CD, CM, CL or a single allowable stress. Take R/V/M/Δ from this page, then run the member through the Wood & Steel Beam module (or your own NDS/AISC checks) for capacity.
#How these numbers are verified
Each case's closed-form values and the finite-element results above come from one shared definition file, evaluated by StructSuite's production beam engine (Hermite-element stiffness solution with consistent nodal loads — reactions are exact to machine precision for the true load positions, and shear is enveloped with support-face statics exactly as the design checks do). The automated test tests/verification/awc-da6-cases.test.ts re-runs all 32 cases on every build and fails if any quantity drifts. The check cuts both ways: a mistyped formula disagrees with the engine, and an engine regression disagrees with the formulas. The largest difference anywhere in the tables above is 0.20% — finite-element discretization at the app's own mesh, on quantities the closed forms give exactly.
#Frequently Asked Questions
#What is the formula for the maximum moment in a simply supported beam?
For a uniformly distributed load, Mmax = wL²/8 at midspan (Figure 1); for a concentrated load at midspan, Mmax = PL/4 (Figure 7); for a concentrated load at any point, Mmax = Pab/L under the load (Figure 8). On this page's 16-ft reference beam those give 3,200 lb·ft, 4,000 lb·ft, and 3,000 lb·ft respectively — each verified against the finite-element engine to within a small fraction of a percent.
#What is the deflection formula for a cantilever beam?
Δmax = wL⁴/8EI at the free end for a uniform load (Figure 12), and Δmax = PL³/3EI for a point load at the tip (Figure 13). Note the contrast with the simple span (5wL⁴/384EI): for the same w, L, and EI the cantilever deflects 48/5 ≈ 9.6 times more — on this page's beam, 3.83 in versus 0.40 in.
#Are these formulas ASD or LRFD?
Neither — they are statics. Reactions, shear, moment, and elastic deflection depend only on geometry, stiffness, and load, not on the design method. ASD vs LRFD enters afterwards, when factored (or unfactored) demands are compared to member capacities. That is also why one engine can serve both the NDS (ASD) wood checks and the AISC (LRFD) steel checks in the beam module: the analysis layer this page verifies is shared.
#Why do the engine results differ from the formulas at all?
Because the engine is a finite-element solution: the beam is meshed into ~2-inch Hermite elements, moment is recovered element by element, and deflection is interpolated between nodes. Reactions come out exact to machine precision; moment and deflection carry discretization differences that stay in the hundredths of a percent at the app's mesh — the largest anywhere on this page is 0.20%. An agreement much tighter than engineering inputs are ever known to (loads are rarely known to 1%) — the point of the comparison is independence, not decimals.
#Where do I get the original AWC Design Aid No. 6?
It's a free PDF from the American Wood Council: AWC DA6 — Beam Design Formulas with Shear and Moment Diagrams. Keep it in the truck; keep this page open next to your model. The figure numbers here match it one for one, so a reviewer can check either source against the other — and the resources directory collects it alongside the NDS, SDPWS, and the other documents a wood-design desk actually uses.
