Wood & Steel Beam

Beam Design Formulas with Shear and Moment Diagrams — All 32 Cases, Worked and Verified

Every classic beam case from AWC Design Aid No. 6 — simple, cantilever, propped, overhanging, fixed-fixed, and two-span continuous — drawn with its shear and moment diagrams, its full formula set, and the SAME 16-ft beam run through each one, so you can see exactly how support conditions and load type change moment, shear, and deflection. Every closed-form value is checked against StructSuite's finite-element beam engine, with the difference printed.

44 min read Updated August 7, 2026
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Every engineer keeps a copy of the classic beam tables within reach — reactions, shear, moment, and deflection formulas for the standard support and loading conditions, best known from the American Wood Council's free Design Aid No. 6, "Beam Design Formulas with Shear and Moment Diagrams" (AWC DA6 — Beam Design Formulas with Shear and Moment Diagrams). This page is a worked companion to those tables, with two things the tables themselves can't show:

  1. One identical beam runs through all 32 cases. Same section, same span, same load intensity — only the supports and load arrangement change. The formulas stop being abstract: you watch Mmax fall from 12,800 lb·ft (cantilever) to 3,200 lb·ft (simple span) to 2,133 lb·ft (fixed ends) for the same 100 plf.
  2. Every closed-form value is checked against an independent calculation. The tables below print each formula's number next to the same quantity computed by StructSuite's finite-element beam engine (the analysis core of the Wood & Steel Beam module), with the difference. The agreement is locked by an automated test — if either side ever drifts, the build fails.

The drawings, layout, and worked numbers here are our own; the case set and figure numbering follow AWC DA6 so you can cross-reference the original PDF line by line. Formulas are the standard closed-form statics results found in every mechanics text.

The setup: one beam, 32 conditions — where each input comes from

Why these inputs. None of the numbers below is code-prescribed — this page verifies statics, so the inputs are chosen to be representative and readable, not to design anything: a 16-ft span and 100 plf are ordinary residential floor-beam territory, 1,000 lb is a round concentrated load big enough that its diagrams read clearly, and the 4-ft overhang and quarter-point positions exercise the a/b/c terms of the formulas. The section only supplies EI (deflection scale); any section would verify the same formulas.

The reference beam. A 4x10 Douglas Fir-Larch No. 2 (E = 1.6 × 106 psi, Ix = 230.8 in4, EI = 369 × 106 lb·in2) — a common sawn beam size, used purely as the analysis section. Self-weight is excluded so the closed forms apply exactly.

The standard inputs, identical in every case they appear: span L = 16 ft (each span, for two-span cases), uniform/peak intensity w = 100 plf, concentrated load P = 1,000 lb, overhang a = 4 ft, second span L2 = 12 ft and second load P2 = 500 lb where a case needs unequal values, and concentrated loads at the quarter point (a = 4 ft) for the "any point" cases.

Notation: L = span length (the classic tables write it as script ℓ — same quantity; we use a plain L so it can never be misread next to E and I); a, b, c = position dimensions; w = load per unit length; W = total load; P = concentrated load; R = reaction; V = shear; M = bending moment; Δ = deflection; E = modulus of elasticity; I = moment of inertia; x = distance from the reaction. Formulas evaluate in inches and lb; this page reports M in lb·ft and Δ in inches.

How to read each card: two sketches, then the two diagrams. The general case comes first, labelled purely with the symbols the formulas use — R1/R2 reaction arrows at the supports, P and w on the loads, the a/b/c/L dimensions as drafting dimension lines. Below it, the same case with this page's numbers (1,000 lb, 100 plf, 4 ft…), so symbol and value line up one over the other. Then the shear and moment diagrams as the engine actually computes them (not schematic shapes — jumps, kinks, and sign reversals are the real solution) with the governing values marked by name (Mmax, M1, Vmax…), the case's full formula set, and the comparison table: closed form vs engine, with the difference. Anchors: link to any case as #fig-N.

Simple beams

One span, a pin and a roller — every other case on this page is a variation on this one. Watch two numbers as the loading changes: Mmax = wL²/8 for the full uniform load (Figure 1) is the yardstick everything else is measured against, and the deflection coefficient collapses fast as load concentrates toward the supports.

Figure 1 — Simple Beam — Uniformly Distributed Load

This run: L = 16 ft, w = 100 plf

GENERAL CASER1R2wLTHIS RUNR1R2100 plf16 ftShear Vmax |V| = 792 lbVmaxMoment Mmax |M| = 3,200 lb·ftMmax

Formula set

  • R = V = wL/2
  • Vx = w(L/2 − x)
  • Mmax (at center) = wL2/8
  • Mx = wx(L − x)/2
  • Δmax (at center) = 5wL4/384EI
  • Δx = wx(L3 − 2Lx2 + x3)/24EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R2wL/2800.0 lb800.0 lb0.00%
VmaxwL/2800.0 lb800.0 lb0.00%
Mmax (at center)wL2/83,200.0 lb·ft3,200.2 lb·ft0.01%
Δmax (at center)5wL4/384EI0.3993 in0.3993 in0.00%

Figure 2 — Simple Beam — Uniform Load Partially Distributed

This run: L = 16 ft, w = 100 plf over the middle b = 8 ft (a = c = 4 ft)

GENERAL CASER1R2wabcLTHIS RUNR1R2100 plf4 ft8 ft4 ft16 ftShear Vmax |V| = 400 lbVmaxMoment Mmax |M| = 2,400 lb·ftMmax

Formula set

  • R1 = V1 (max when a < c) = wb(2c + b)/2L
  • R2 = V2 (max when a > c) = wb(2a + b)/2L
  • Vx (when x > a and < (a + b)) = R1 − w(x − a)
  • Mmax (at x = a + R1/w) = R1(a + R1/2w)
  • Mx (when x < a) = R1x
  • Mx (when x > a and < (a + b)) = R1x − w(x − a)2/2
  • Mx (when x > (a + b)) = R2(L − x)
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R2wb(2c + b)/2L400.0 lb400.0 lb0.00%
VmaxR1400.0 lb400.0 lb0.00%
Mmax (at x = a + R1/w)R1(a + R1/2w)2,400.0 lb·ft2,400.2 lb·ft0.01%

Figure 3 — Simple Beam — Uniform Load Partially Distributed at One End

This run: L = 16 ft, w = 100 plf over the left a = 8 ft

GENERAL CASER1R2waLTHIS RUNR1R2100 plf8 ft8 ft16 ftShear Vmax |V| = 592 lbVmaxMoment Mmax |M| = 1,800 lb·ftMmax

Formula set

  • R1 = V1 = wa(2L − a)/2L
  • R2 = V2 = wa2/2L
  • Vx (when x < a) = R1 − wx
  • Mmax (at x = R1/w) = R12/2w
  • Mx (when x < a) = R1x − wx2/2
  • Mx (when x > a) = R2(L − x)
  • Δx (when x < a) = wx[a2(2L − a)2 − 2ax2(2L − a) + Lx3]/24EIL
  • Δx (when x > a) = wa2(L − x)(4xL − 2x2 − a2)/24EIL
QuantityGoverning formulaClosed formStructSuite engineDiff
R1wa(2L − a)/2L600.0 lb600.0 lb0.00%
R2wa2/2L200.0 lb200.0 lb0.00%
VmaxR1600.0 lb600.0 lb0.00%
Mmax (at x = R1/w)R12/2w1,800.0 lb·ft1,800.2 lb·ft0.01%

Figure 4 — Simple Beam — Uniform Load Partially Distributed at Each End

This run: L = 16 ft, w1 = w2 = 100 plf over a = c = 4 ft at each end

GENERAL CASER1R2w1w2abcLTHIS RUNR1R2100 plf100 plf4 ft8 ft4 ft16 ftShear Vmax |V| = 392 lbVmaxMoment Mmax |M| = 800 lb·ftMmax

Formula set

  • R1 = V1 = [w1a(2L − a) + w2c2]/2L
  • R2 = V2 = [w2c(2L − c) + w1a2]/2L
  • Vx (when x < a) = R1 − w1x
  • Vx (when x > a and < (a + b)) = R1 − w1a
  • Vx (when x > (a + b)) = R2 − w2(L − x)
  • Mmax (at x = R1/w1 when R1 < w1a) = R12/2w1
  • Mmax (at x = L − R2/w2 when R2 < w2c) = R22/2w2
  • Mx (when x < a) = R1x − w1x2/2
  • Mx (when x > a and < (a + b)) = R1x − w1a(2x − a)/2
  • Mx (when x > (a + b)) = R2(L − x) − w2(L − x)2/2
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R2[w1a(2L − a) + w2c2]/2L400.0 lb400.0 lb0.00%
VmaxR1400.0 lb400.0 lb0.00%
Mmax (at x = R1/w1)R12/2w1800.0 lb·ft800.2 lb·ft0.03%

Figure 5 — Simple Beam — Load Increasing Uniformly to One End

This run: L = 16 ft, 0 → 100 plf (total W = 800 lb, peak at R2)

GENERAL CASER1R2WLTHIS RUNR1R2800 lb16 ftShear Vmax |V| = 525 lbVmaxMoment Mmax |M| = 1,642 lb·ftMmax

Formula set

  • R1 = V1 = W/3
  • R2 = V2 = 2W/3
  • Vx = W/3 − Wx2/L2
  • Mmax (at x = L/√3 = 0.5774L) = 2WL/9√3 = 0.1283WL
  • Mx = Wx(L2 − x2)/3L2
  • Δmax (at x = L√(1 − √(8/15)) = 0.5193L) = 0.01304WL3/EI
  • Δx = Wx(3x4 − 10L2x2 + 7L4)/180EIL2
QuantityGoverning formulaClosed formStructSuite engineDiff
R1W/3266.7 lb266.7 lb0.00%
R22W/3533.3 lb533.3 lb0.00%
Vmax2W/3533.3 lb533.3 lb0.00%
Mmax (at 0.5774L)0.1283WL1,642.2 lb·ft1,642.2 lb·ft0.00%
Δmax (at 0.5193L)0.01304WL3/EI0.1999 in0.2000 in0.03%

Figure 6 — Simple Beam — Load Increasing Uniformly to Center

This run: L = 16 ft, 0 → 100 plf → 0 (total W = 800 lb, peak at center)

GENERAL CASER1R2WL/2L/2THIS RUNR1R2800 lb8 ft8 ftShear Vmax |V| = 400 lbVmaxMoment Mmax |M| = 2,134 lb·ftMmax

Formula set

  • R = V = W/2
  • Vx (when x < L/2) = W(L2 − 4x2)/2L2
  • Mmax (at center) = WL/6
  • Mx (when x < L/2) = Wx(1/2 − 2x2/3L2)
  • Δmax (at center) = WL3/60EI
  • Δx = Wx(5L2 − 4x2)2/480EIL2
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R2W/2400.0 lb400.0 lb0.00%
VmaxW/2400.0 lb400.0 lb0.00%
Mmax (at center)WL/62,133.3 lb·ft2,133.6 lb·ft0.01%
Δmax (at center)WL3/60EI0.2556 in0.2556 in0.00%

Figure 7 — Simple Beam — Concentrated Load at Center

This run: L = 16 ft, P = 1,000 lb at midspan

GENERAL CASER1R2PL/2L/2THIS RUNR1R21,000 lb8 ft8 ftShear Vmax |V| = 500 lbVmaxMoment Mmax |M| = 4,000 lb·ftMmax

Formula set

  • R = V = P/2
  • Mmax (at point of load) = PL/4
  • Mx (when x < L/2) = Px/2
  • Δmax (at point of load) = PL3/48EI
  • Δx (when x < L/2) = Px(3L2 − 4x2)/48EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R2P/2500.0 lb500.0 lb0.00%
VmaxP/2500.0 lb500.0 lb0.00%
Mmax (at center)PL/44,000.0 lb·ft4,000.0 lb·ft0.00%
Δmax (at center)PL3/48EI0.3993 in0.3993 in0.00%

Figure 8 — Simple Beam — Concentrated Load at Any Point

This run: L = 16 ft, P = 1,000 lb at a = 4 ft (b = 12 ft)

GENERAL CASER1R2PabLTHIS RUNR1R21,000 lb4 ft12 ft16 ftShear Vmax |V| = 750 lbVmaxMoment Mmax |M| = 3,000 lb·ftMmax

Formula set

  • R1 = V1 (max when a < b) = Pb/L
  • R2 = V2 (max when a > b) = Pa/L
  • Mmax (at point of load) = Pab/L
  • Mx (when x < a) = Pbx/L
  • Δmax (at x = √(a(a + 2b)/3) when a > b) = Pab(a + 2b)√(3a(a + 2b))/27EIL
  • Δa (at point of load) = Pa2b2/3EIL
  • Δx (when x < a) = Pbx(L2 − b2 − x2)/6EIL
  • Δx (when x > a) = Pa(L − x)(2Lx − x2 − a2)/6EIL
QuantityGoverning formulaClosed formStructSuite engineDiff
R1Pb/L750.0 lb750.0 lb0.00%
R2Pa/L250.0 lb250.0 lb0.00%
VmaxPb/L750.0 lb750.0 lb0.00%
Mmax (at point of load)Pab/L3,000.0 lb·ft3,000.0 lb·ft0.00%
ΔmaxPab(a + 2b)√(3a(a + 2b))/27EIL0.2790 in0.2790 in0.00%

Figure 9 — Simple Beam — Two Equal Concentrated Loads Symmetrically Placed

This run: L = 16 ft, P = 1,000 lb each at a = 4 ft from each end

GENERAL CASER1R2PPaaLTHIS RUNR1R21,000 lb1,000 lb4 ft8 ft4 ft16 ftShear Vmax |V| = 1,000 lbVmaxMoment Mmax |M| = 4,000 lb·ftMmax

Formula set

  • R = V = P
  • Mmax (between loads) = Pa
  • Mx (when x < a) = Px
  • Δmax (at center) = Pa(3L2 − 4a2)/24EI
  • Δx (when x < a) = Px(3La − 3a2 − x2)/6EI
  • Δx (when x > a and < (L − a)) = Pa(3Lx − 3x2 − a2)/6EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R2P1,000.0 lb1,000.0 lb0.00%
VmaxP1,000.0 lb1,000.0 lb0.00%
Mmax (between loads)Pa4,000.0 lb·ft4,000.0 lb·ft0.00%
Δmax (at center)Pa(3L2 − 4a2)/24EI0.5490 in0.5490 in0.00%

Figure 10 — Simple Beam — Two Equal Concentrated Loads Unsymmetrically Placed

This run: L = 16 ft, P = 1,000 lb each at a = 4 ft from the left and b = 6 ft from the right

GENERAL CASER1R2PPabLTHIS RUNR1R21,000 lb1,000 lb4 ft6 ft6 ft16 ftShear Vmax |V| = 1,125 lbVmaxMoment Mmax |M| = 5,250 lb·ftM2

Formula set

  • R1 = V1 (max when a < b) = P(L − a + b)/L
  • R2 = V2 (max when a > b) = P(L − b + a)/L
  • Vx (when x > a and < (L − b)) = P(b − a)/L
  • M1 (max when a > b) = R1a
  • M2 (max when a < b) = R2b
  • Mx (when x < a) = R1x
  • Mx (when x > a and < (L − b)) = R1x − P(x − a)
QuantityGoverning formulaClosed formStructSuite engineDiff
R1P(L − a + b)/L1,125.0 lb1,125.0 lb0.00%
R2P(L − b + a)/L875.0 lb875.0 lb0.00%
VmaxR11,125.0 lb1,125.0 lb0.00%
M2 (at the second load)R2b5,250.0 lb·ft5,250.0 lb·ft0.00%

Figure 11 — Simple Beam — Two Unequal Concentrated Loads Unsymmetrically Placed

This run: L = 16 ft, P1 = 1,000 lb at a = 4 ft, P2 = 500 lb at b = 6 ft from the right

GENERAL CASER1R2P1P2abLTHIS RUNR1R21,000 lb500 lb4 ft6 ft6 ft16 ftShear Vmax |V| = 938 lbVmaxMoment Mmax |M| = 3,750 lb·ftM1

Formula set

  • R1 = V1 = [P1(L − a) + P2b]/L
  • R2 = V2 = [P1a + P2(L − b)]/L
  • Vx (when x > a and < (L − b)) = R1 − P1
  • M1 (max when R1 < P1) = R1a
  • M2 (max when R2 < P2) = R2b
  • Mx (when x < a) = R1x
  • Mx (when x > a and < (L − b)) = R1x − P1(x − a)
QuantityGoverning formulaClosed formStructSuite engineDiff
R1[P1(L − a) + P2b]/L937.5 lb937.5 lb0.00%
R2[P1a + P2(L − b)]/L562.5 lb562.5 lb0.00%
VmaxR1937.5 lb937.5 lb0.00%
M1 (at P1)R1a3,750.0 lb·ft3,750.0 lb·ft0.00%

Cantilever beams

Fix one end, free the other. The moment arm doubles and the coefficient jumps from wL²/8 to wL²/2 — four times the simple-span moment for the same load — and deflection grows almost an order of magnitude. This is why the same section that works fine on a simple span is rarely adequate as a full-length cantilever.

Figure 12 — Cantilever Beam — Uniformly Distributed Load

This run: L = 16 ft, w = 100 plf, fixed at the right end

GENERAL CASERwLTHIS RUNR100 plf16 ftShear Vmax |V| = 1,592 lbVmaxMoment Mmax |M| = 12,800 lb·ftMmax

Formula set

  • R = V = wL
  • Vx = wx (x from the free end)
  • Mmax (at fixed end) = wL2/2
  • Mx = wx2/2
  • Δmax (at free end) = wL4/8EI
  • Δx = w(x4 − 4L3x + 3L4)/24EI
QuantityGoverning formulaClosed formStructSuite engineDiff
RwL1,600.0 lb1,600.0 lb0.00%
VmaxwL1,600.0 lb1,600.0 lb0.00%
Mmax (at fixed end)wL2/212,800.0 lb·ft12,799.8 lb·ft0.00%
Δmax (at free end)wL4/8EI3.8333 in3.8333 in0.00%

Figure 13 — Cantilever Beam — Concentrated Load at Free End

This run: L = 16 ft, P = 1,000 lb at the free end, fixed at the right end

GENERAL CASERPLTHIS RUNR1,000 lb16 ftShear Vmax |V| = 1,000 lbVmaxMoment Mmax |M| = 16,000 lb·ftMmax

Formula set

  • R = V = P
  • Mmax (at fixed end) = PL
  • Mx = Px (x from the free end)
  • Δmax (at free end) = PL3/3EI
  • Δx = P(2L3 − 3L2x + x3)/6EI
QuantityGoverning formulaClosed formStructSuite engineDiff
RP1,000.0 lb1,000.0 lb0.00%
VmaxP1,000.0 lb1,000.0 lb0.00%
Mmax (at fixed end)PL16,000.0 lb·ft16,000.0 lb·ft0.00%
Δmax (at free end)PL3/3EI6.3889 in6.3889 in0.00%

Figure 14 — Cantilever Beam — Concentrated Load at Any Point

This run: L = 16 ft, P = 1,000 lb at a = 4 ft from the free end (b = 12 ft to the fixed end)

GENERAL CASERPabLTHIS RUNR1,000 lb4 ft12 ft16 ftShear Vmax |V| = 1,000 lbVmaxMoment Mmax |M| = 12,000 lb·ftMmax

Formula set

  • R = V = P
  • Mmax (at fixed end) = Pb
  • Mx (when x > a) = P(x − a) (x from the free end)
  • Δmax (at free end) = Pb2(3L − b)/6EI
  • Δa (at point of load) = Pb3/3EI
  • Δx (when x < a) = Pb2(3L − 3x − b)/6EI
  • Δx (when x > a) = P(L − x)2(3b − L + x)/6EI
QuantityGoverning formulaClosed formStructSuite engineDiff
RP1,000.0 lb1,000.0 lb0.00%
VmaxP1,000.0 lb1,000.0 lb0.00%
Mmax (at fixed end)Pb12,000.0 lb·ft12,000.0 lb·ft0.00%
Δmax (at free end)Pb2(3L − b)/6EI4.0430 in4.0430 in0.00%

Propped cantilevers (fixed at one end, supported at the other)

Adding a simple support to a cantilever (or fixing one end of a simple beam) makes the beam statically indeterminate: the fixed end picks up 5/8 of a uniform load, the moment splits into a hogging peak at the wall (wL²/8) and a smaller sagging peak (9wL²/128), and deflection drops to less than half the simple span’s.

Figure 15 — Beam Fixed at One End, Supported at Other — Uniformly Distributed Load

This run: L = 16 ft, w = 100 plf, simple support left (R1), fixed right (R2)

GENERAL CASER1R2wLTHIS RUNR1R2100 plf16 ftShear Vmax |V| = 992 lbVmaxMoment Mmax |M| = 3,200 lb·ftM1Mmax

Formula set

  • R1 = V1 = 3wL/8
  • R2 = V2 = 5wL/8
  • Vx = R1 − wx
  • Mmax (at fixed end) = wL2/8
  • M1 (at x = 3L/8) = 9wL2/128
  • Mx = R1x − wx2/2
  • Δmax (at x = (L/16)(1 + √33) = 0.4215L) = wL4/185EI
  • Δx = wx(L3 − 3Lx2 + 2x3)/48EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 (simple end)3wL/8600.0 lb600.0 lb0.00%
R2 (fixed end)5wL/81,000.0 lb1,000.0 lb0.00%
Vmax5wL/81,000.0 lb1,000.0 lb0.00%
Mmax (at fixed end)wL2/83,200.0 lb·ft3,199.8 lb·ft0.01%
M1 (at 3L/8)9wL2/1281,800.0 lb·ft1,800.2 lb·ft0.01%
Δmax (at 0.4215L)wL4/185EI0.1658 in0.1661 in0.20%

Figure 16 — Beam Fixed at One End, Supported at Other — Concentrated Load at Center

This run: L = 16 ft, P = 1,000 lb at midspan, simple left, fixed right

GENERAL CASER1R2PL/2L/2THIS RUNR1R21,000 lb8 ft8 ftShear Vmax |V| = 688 lbVmaxMoment Mmax |M| = 3,000 lb·ftM1Mmax

Formula set

  • R1 = V1 = 5P/16
  • R2 = V2 = 11P/16
  • Mmax (at fixed end) = 3PL/16
  • M1 (at point of load) = 5PL/32
  • Mx (when x < L/2) = 5Px/16
  • Mx (when x > L/2) = P(L/2 − 11x/16)
  • Δmax (at x = L√(1/5) = 0.4472L) = PL3/48EI√5 = 0.009317PL3/EI
  • Δx (at point of load) = 7PL3/768EI
  • Δx (when x < L/2) = Px(3L2 − 5x2)/96EI
  • Δx (when x > L/2) = P(x − L)2(11x − 2L)/96EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 (simple end)5P/16312.5 lb312.5 lb0.00%
R2 (fixed end)11P/16687.5 lb687.5 lb0.00%
Vmax11P/16687.5 lb687.5 lb0.00%
Mmax (at fixed end)3PL/163,000.0 lb·ft3,000.0 lb·ft0.00%
M1 (at point of load)5PL/322,500.0 lb·ft2,500.0 lb·ft0.00%
Δmax (at 0.4472L)0.009317PL3/EI0.1786 in0.1786 in0.00%

Figure 17 — Beam Fixed at One End, Supported at Other — Concentrated Load at Any Point

This run: L = 16 ft, P = 1,000 lb at a = 4 ft from the simple support (b = 12 ft)

GENERAL CASER1R2PabLTHIS RUNR1R21,000 lb4 ft12 ft16 ftShear Vmax |V| = 633 lbVmaxMoment Mmax |M| = 2,531 lb·ftM1M2

Formula set

  • R1 = V1 = Pb2(a + 2L)/2L3
  • R2 = V2 = Pa(3L2 − a2)/2L3
  • M1 (at point of load) = R1a
  • M2 (at fixed end) = Pab(a + L)/2L2
  • Mx (when x < a) = R1x
  • Mx (when x > a) = R1x − P(x − a)
  • Δmax (when a < 0.414L, at x = L(L2 + a2)/(3L2 − a2)) = Pa(L2 − a2)3/3EI(3L2 − a2)2
  • Δmax (when a > 0.414L, at x = L√(a/(2L + a))) = Pab2√(a/(2L + a))/6EI
  • Δa (at point of load) = Pa2b3(3L + a)/12EIL3
  • Δx (when x < a) = Pb2x(3aL2 − 2Lx2 − ax2)/12EIL3
  • Δx (when x > a) = Pa(L − x)2(3L2x − a2x − 2a2L)/12EIL3
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 (simple end)Pb2(a + 2L)/2L3632.8 lb632.8 lb0.00%
R2 (fixed end)Pa(3L2 − a2)/2L3367.2 lb367.2 lb0.00%
VmaxR1632.8 lb632.8 lb0.00%
M1 (at point of load)R1a2,531.3 lb·ft2,531.3 lb·ft0.00%
M2 (at fixed end)Pab(a + L)/2L21,875.0 lb·ft1,875.0 lb·ft0.00%
ΔmaxPa(L2 − a2)3/3EI(3L2 − a2)20.1525 in0.1525 in0.00%

Overhanging beams

Push the beam past its support and the hogging moment over that support (wa²/2 or Pa) fights the sagging moment between supports. A short overhang barely dents the span moment; load only the overhang and the far reaction goes negative — the beam tries to lift off its first support.

Figure 18 — Beam Overhanging One Support — Uniformly Distributed Load

This run: L = 16 ft between supports, a = 4 ft overhang, w = 100 plf over the whole length

GENERAL CASER1R2wLaTHIS RUNR1R2100 plf16 ft4 ftShear Vmax |V| = 842 lbVmaxMoment Mmax |M| = 2,813 lb·ftM1M2

Formula set

  • R1 = V1 = w(L2 − a2)/2L
  • R2 = V2 + V3 = w(L + a)2/2L
  • V2 = wa
  • V3 = w(L2 + a2)/2L
  • Vx (between supports) = R1 − wx
  • Vx1 (for overhang) = w(a − x1)
  • M1 (at x = (L/2)(1 − a2/L2)) = w(L + a)2(L − a)2/8L2
  • M2 (at R2) = wa2/2
  • Mx (between supports) = wx(L2 − a2 − xL)/2L
  • Mx1 (for overhang) = w(a − x1)2/2
  • Δx (between supports) = wx(L4 − 2L2x2 + Lx3 − 2a2L2 + 2a2x2)/24EIL
  • Δx1 (for overhang) = wx1(4a2L − L3 + 6a2x1 − 4ax12 + x13)/24EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1w(L2 − a2)/2L750.0 lb750.0 lb0.00%
R2w(L + a)2/2L1,250.0 lb1,250.0 lb0.00%
VmaxV3 = w(L2 + a2)/2L850.0 lb850.0 lb0.00%
M1 (between supports)w(L + a)2(L − a)2/8L22,812.5 lb·ft2,812.7 lb·ft0.01%
M2 (at R2)wa2/2800.0 lb·ft799.8 lb·ft0.03%

Figure 19 — Beam Overhanging One Support — Uniformly Distributed Load on Overhang

This run: L = 16 ft between supports, a = 4 ft overhang, w = 100 plf on the overhang only

GENERAL CASER1R2wLaTHIS RUNR1R2100 plf16 ft4 ftShear Vmax |V| = 392 lbVmaxMoment Mmax |M| = 800 lb·ftMmax

Formula set

  • R1 = V1 = wa2/2L (downward)
  • R2 = V1 + V2 = wa(2L + a)/2L
  • V2 = wa
  • Vx1 (for overhang) = w(a − x1)
  • Mmax (at R2) = wa2/2
  • Mx (between supports) = wa2x/2L
  • Mx1 (for overhang) = w(a − x1)2/2
  • Δmax (between supports, at x = L/√3) = wa2L2/18√3EI = 0.03208wa2L2/EI
  • Δmax (for overhang, at x1 = a) = wa3(4L + 3a)/24EI
  • Δx (between supports) = wa2x(L2 − x2)/12EIL
  • Δx1 (for overhang) = wx1(4a2L + 6a2x1 − 4ax12 + x13)/24EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1−wa2/2L-50.0 lb-50.0 lb0.00%
R2wa(2L + a)/2L450.0 lb450.0 lb0.00%
VmaxV2 = wa400.0 lb400.0 lb0.00%
Mmax (at R2)wa2/2800.0 lb·ft800.0 lb·ft0.00%
Δmax (between supports)0.03208wa2L2/EI0.0615 in0.0615 in0.02%
Δmax (overhang tip)wa3(4L + 3a)/24EI0.0948 in0.0948 in0.00%

Figure 20 — Beam Overhanging One Support — Concentrated Load at End of Overhang

This run: L = 16 ft between supports, a = 4 ft overhang, P = 1,000 lb at the tip

GENERAL CASER1R2PLaTHIS RUNR1R21,000 lb16 ft4 ftShear Vmax |V| = 1,000 lbVmaxMoment Mmax |M| = 4,000 lb·ftMmax

Formula set

  • R1 = V1 = Pa/L (downward)
  • R2 = V1 + V2 = P(L + a)/L
  • V2 = P
  • Mmax (at R2) = Pa
  • Mx (between supports) = Pax/L
  • Mx1 (for overhang) = P(a − x1)
  • Δmax (between supports, at x = L/√3) = PaL2/9√3EI = 0.06415PaL2/EI
  • Δmax (for overhang, at x1 = a) = Pa2(L + a)/3EI
  • Δx (between supports) = Pax(L2 − x2)/6EIL
  • Δx1 (for overhang) = Px1(2aL + 3ax1 − x12)/6EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1−Pa/L-250.0 lb-250.0 lb0.00%
R2P(L + a)/L1,250.0 lb1,250.0 lb0.00%
VmaxV2 = P1,000.0 lb1,000.0 lb0.00%
Mmax (at R2)Pa4,000.0 lb·ft4,000.0 lb·ft0.00%
Δmax (between supports)0.06415PaL2/EI0.3074 in0.3074 in0.00%
Δmax (overhang tip)Pa2(L + a)/3EI0.4991 in0.4991 in0.00%

Figure 21 — Beam Overhanging One Support — Concentrated Load at Any Point Between Supports

This run: L = 16 ft between supports, a = 4 ft overhang, P = 1,000 lb at a = 4 ft from R1

GENERAL CASER1R2PabLTHIS RUNR1R21,000 lb4 ft12 ft4 ft16 ftShear Vmax |V| = 750 lbVmaxMoment Mmax |M| = 3,000 lb·ftMmax

Formula set

  • R1 = V1 (max when a < b) = Pb/L
  • R2 = V2 (max when a > b) = Pa/L
  • Mmax (at point of load) = Pab/L
  • Mx (when x < a) = Pbx/L
  • Δmax (at x = √(a(a + 2b)/3) when a > b) = Pab(a + 2b)√(3a(a + 2b))/27EIL
  • Δa (at point of load) = Pa2b2/3EIL
  • Δx (when x < a) = Pbx(L2 − b2 − x2)/6EIL
  • Δx (when x > a) = Pa(L − x)(2Lx − x2 − a2)/6EIL
  • Δx1 (for overhang) = Pabx1(L + a)/6EIL
QuantityGoverning formulaClosed formStructSuite engineDiff
R1Pb/L750.0 lb750.0 lb0.00%
R2Pa/L250.0 lb250.0 lb0.00%
VmaxPb/L750.0 lb750.0 lb0.00%
Mmax (at point of load)Pab/L3,000.0 lb·ft3,000.0 lb·ft0.00%
Δmax (between supports)Pab(a + 2b)√(3a(a + 2b))/27EIL0.2790 in0.2790 in0.00%
Δ (overhang tip, x1 = a)Pabx1(L + a)/6EIL0.1872 in0.1872 in0.00%

Figure 22 — Beam Overhanging Both Supports — Unequal Overhangs — Uniformly Distributed Load

This run: span b = 16 ft, overhangs a = 4 ft and c = 2 ft (total L = 22 ft), w = 100 plf over the whole length

GENERAL CASER1R2wabcLTHIS RUNR1R2100 plf4 ft16 ft2 ft22 ftShear Vmax |V| = 829 lbVmaxMoment Mmax |M| = 2,707 lb·ftM3M1

Formula set

  • R1 = wL(L − 2c)/2b
  • R2 = wL(L − 2a)/2b
  • V1 = wa;  V2 = R1 − V1;  V3 = R2 − V4;  V4 = wc
  • Vx1 = V1 − wx1
  • Vx (when x < L) = R1 − w(a + x)
  • Vm (when a < c) = R2 − wc
  • M1 = −wa2/2
  • M2 = −wc2/2
  • M3 = R1(R1/2w − a)
  • Mx (max when x = R1/w − a) = R1x − w(a + x)2/2
QuantityGoverning formulaClosed formStructSuite engineDiff
R1wL(L − 2c)/2b1,237.5 lb1,237.5 lb0.00%
R2wL(L − 2a)/2b962.5 lb962.5 lb0.00%
VmaxV2 = R1 − wa837.5 lb837.5 lb0.00%
M3 (between supports)R1(R1/2w − a)2,707.0 lb·ft2,707.2 lb·ft0.01%
M1 (at R1)wa2/2800.0 lb·ft799.8 lb·ft0.03%

Fixed-fixed beams

Full end restraint is the stiffest condition here: the uniform-load moment drops to wL²/12 at the walls (and wL²/24 at midspan), and deflection is a fifth of the simple span’s. The price is real end moments the connections must actually develop — which is why true fixity is rare in wood construction.

Figure 23 — Beam Fixed at Both Ends — Uniformly Distributed Load

This run: L = 16 ft, w = 100 plf

GENERAL CASER1R2wLTHIS RUNR1R2100 plf16 ftShear Vmax |V| = 792 lbVmaxMoment Mmax |M| = 2,133 lb·ftM1Mmax

Formula set

  • R = V = wL/2
  • Vx = w(L/2 − x)
  • Mmax (at ends) = wL2/12
  • M1 (at center) = wL2/24
  • Mx = w(6Lx − L2 − 6x2)/12
  • Δmax (at center) = wL4/384EI
  • Δx = wx2(L − x)2/24EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R2wL/2800.0 lb800.0 lb0.00%
VmaxwL/2800.0 lb800.0 lb0.00%
Mmax (at ends)wL2/122,133.3 lb·ft2,133.1 lb·ft0.01%
M1 (at center)wL2/241,066.7 lb·ft1,066.9 lb·ft0.02%
Δmax (at center)wL4/384EI0.0799 in0.0799 in0.00%

Figure 24 — Beam Fixed at Both Ends — Concentrated Load at Center

This run: L = 16 ft, P = 1,000 lb at midspan

GENERAL CASER1R2PL/2L/2THIS RUNR1R21,000 lb8 ft8 ftShear Vmax |V| = 500 lbVmaxMoment Mmax |M| = 2,000 lb·ftMmaxMmax

Formula set

  • R = V = P/2
  • Mmax (at center and ends) = PL/8
  • Mx (when x < L/2) = P(4x − L)/8
  • Δmax (at center) = PL3/192EI
  • Δx (when x < L/2) = Px2(3L − 4x)/48EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R2P/2500.0 lb500.0 lb0.00%
VmaxP/2500.0 lb500.0 lb0.00%
Mmax (at center)PL/82,000.0 lb·ft2,000.0 lb·ft0.00%
Mmax (at ends)PL/82,000.0 lb·ft2,000.0 lb·ft0.00%
Δmax (at center)PL3/192EI0.0998 in0.0998 in0.00%

Figure 25 — Beam Fixed at Both Ends — Concentrated Load at Any Point

This run: L = 16 ft, P = 1,000 lb at a = 4 ft (b = 12 ft)

GENERAL CASER1R2PabLTHIS RUNR1R21,000 lb4 ft12 ft16 ftShear Vmax |V| = 844 lbVmaxMoment Mmax |M| = 2,250 lb·ftMaM1

Formula set

  • R1 = V1 (max when a < b) = Pb2(3a + b)/L3
  • R2 = V2 (max when a > b) = Pa2(a + 3b)/L3
  • M1 (max when a < b) = Pab2/L2
  • M2 (max when a > b) = Pa2b/L2
  • Ma (at point of load) = 2Pa2b2/L3
  • Mx (when x < a) = R1x − Pab2/L2
  • Δmax (when a > b, at x = 2aL/(3a + b)) = 2Pa3b2/3EI(3a + b)2
  • Δa (at point of load) = Pa3b3/3EIL3
  • Δx (when x < a) = Pb2x2(3aL − 3ax − bx)/6EIL3
QuantityGoverning formulaClosed formStructSuite engineDiff
R1Pb2(3a + b)/L3843.8 lb843.7 lb0.00%
R2Pa2(a + 3b)/L3156.3 lb156.2 lb0.00%
VmaxR1843.8 lb843.8 lb0.00%
M1 (at the near fixed end)Pab2/L22,250.0 lb·ft2,250.0 lb·ft0.00%
Ma (at point of load)2Pa2b2/L31,125.0 lb·ft1,125.0 lb·ft0.00%
Δmax2Pa3b2/3EI(3a + b)20.0539 in0.0539 in0.00%

Two-span continuous beams

Continuity trades midspan moment for a hogging peak over the center support (wL²/8 for both spans loaded) and an uplift surprise: load ONE span and the far-end reaction goes negative. The center support collects 10/8 of wL — the reaction the post and footing below must be designed for.

Figure 26 — Continuous Beam — Two Equal Spans — Uniform Load on One Span

This run: two 16-ft spans, w = 100 plf on the first span only

GENERAL CASER1R2R3wLLTHIS RUNR1R2R3100 plf16 ft16 ftShear Vmax |V| = 892 lbVmaxMoment Mmax |M| = 2,450 lb·ftMmaxM1

Formula set

  • R1 = V1 = 7wL/16
  • R2 = V2 + V3 = 5wL/8
  • R3 = V3 = −wL/16
  • V2 = 9wL/16
  • Mmax (at x = 7L/16) = 49wL2/512
  • M1 (at support R2) = wL2/16
  • Mx (when x < L) = wx(7L − 8x)/16
QuantityGoverning formulaClosed formStructSuite engineDiff
R17wL/16700.0 lb700.0 lb0.00%
R25wL/81,000.0 lb1,000.0 lb0.00%
R3−wL/16-100.0 lb-100.0 lb0.00%
VmaxV2 = 9wL/16900.0 lb900.0 lb0.00%
Mmax (at 7L/16)49wL2/5122,450.0 lb·ft2,450.2 lb·ft0.01%
M1 (at R2)wL2/161,600.0 lb·ft1,600.0 lb·ft0.00%

Figure 27 — Continuous Beam — Two Equal Spans — Concentrated Load at Center of One Span

This run: two 16-ft spans, P = 1,000 lb at the center of the first span

GENERAL CASER1R2R3PL/2L/2LTHIS RUNR1R2R31,000 lb8 ft8 ft16 ftShear Vmax |V| = 594 lbVmaxMoment Mmax |M| = 3,250 lb·ftMmaxM1

Formula set

  • R1 = V1 = 13P/32
  • R2 = V2 + V3 = 11P/16
  • R3 = V3 = −3P/32
  • V2 = 19P/32
  • Mmax (at point of load) = 13PL/64
  • M1 (at support R2) = 3PL/32
QuantityGoverning formulaClosed formStructSuite engineDiff
R113P/32406.3 lb406.3 lb0.00%
R211P/16687.5 lb687.5 lb0.00%
R3−3P/32-93.8 lb-93.8 lb0.00%
VmaxV2 = 19P/32593.8 lb593.8 lb0.00%
Mmax (at point of load)13PL/643,250.0 lb·ft3,250.0 lb·ft0.00%
M1 (at R2)3PL/321,500.0 lb·ft1,500.0 lb·ft0.00%

Figure 28 — Continuous Beam — Two Equal Spans — Concentrated Load at Any Point

This run: two 16-ft spans, P = 1,000 lb at a = 4 ft into the first span (b = 12 ft)

GENERAL CASER1R2R3PabLTHIS RUNR1R2R31,000 lb4 ft12 ft16 ftShear Vmax |V| = 691 lbVmaxMoment Mmax |M| = 2,766 lb·ftMmaxM1

Formula set

  • R1 = V1 = Pb[4L2 − a(L + a)]/4L3
  • R2 = V2 + V3 = Pa[2L2 + b(L + a)]/2L3
  • R3 = V3 = −Pab(L + a)/4L3
  • V2 = Pa[4L2 + b(L + a)]/4L3
  • Mmax (at point of load) = Pb[4L2 − a(L + a)]a/4L3
  • M1 (at support R2) = Pab(L + a)/4L2
QuantityGoverning formulaClosed formStructSuite engineDiff
R1Pb[4L2 − a(L + a)]/4L3691.4 lb691.4 lb0.00%
R2Pa[2L2 + b(L + a)]/2L3367.2 lb367.2 lb0.00%
R3−Pab(L + a)/4L3-58.6 lb-58.6 lb0.00%
VmaxR1691.4 lb691.4 lb0.00%
Mmax (at point of load)R1a2,765.6 lb·ft2,765.6 lb·ft0.00%
M1 (at R2)Pab(L + a)/4L2937.5 lb·ft937.5 lb·ft0.00%

Figure 29 — Continuous Beam — Two Equal Spans — Uniformly Distributed Load

This run: two 16-ft spans, w = 100 plf on both spans

GENERAL CASER1R2R3wLLTHIS RUNR1R2R3100 plf16 ft16 ftShear Vmax |V| = 992 lbVmaxMoment Mmax |M| = 3,200 lb·ftM2M1

Formula set

  • R1 = V1 = R3 = V3 = 3wL/8
  • R2 = 10wL/8
  • V2 = Vmax = 5wL/8
  • M1 (at support R2) = wL2/8
  • M2 (at 3L/8) = 9wL2/128
  • Δmax (at 0.4215L from R1 and R3) = wL4/185EI
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R33wL/8600.0 lb600.0 lb0.00%
R210wL/82,000.0 lb2,000.0 lb0.00%
Vmax5wL/81,000.0 lb1,000.0 lb0.00%
M1 (at R2)wL2/83,200.0 lb·ft3,199.8 lb·ft0.01%
M2 (at 3L/8)9wL2/1281,800.0 lb·ft1,800.2 lb·ft0.01%
Δmax (at 0.4215L)wL4/185EI0.1658 in0.1661 in0.20%

Figure 30 — Continuous Beam — Two Equal Spans — Two Equal Concentrated Loads Symmetrically Placed

This run: two 16-ft spans, P = 1,000 lb at the center of each span (a = L/2)

GENERAL CASER1R2R3PPaaaaTHIS RUNR1R2R31,000 lb1,000 lb8 ft8 ft8 ft8 ftShear Vmax |V| = 688 lbVmaxMoment Mmax |M| = 3,000 lb·ftM2M1

Formula set

  • R1 = V1 = R3 = V3 = 5P/16
  • R2 = 2V2 = 11P/8
  • V2 = P − R1 = 11P/16
  • Vmax = V2
  • M1 = −3PL/16
  • M2 = 5PL/32
  • Mx (when x < a) = R1x
QuantityGoverning formulaClosed formStructSuite engineDiff
R1 = R35P/16312.5 lb312.5 lb0.00%
R211P/81,375.0 lb1,375.0 lb0.00%
Vmax11P/16687.5 lb687.5 lb0.00%
M1 (at R2)3PL/163,000.0 lb·ft3,000.0 lb·ft0.00%
M2 (at loads)5PL/322,500.0 lb·ft2,500.0 lb·ft0.00%

Figure 31 — Continuous Beam — Two Unequal Spans — Uniformly Distributed Load

This run: spans L1 = 16 ft and L2 = 12 ft, w = 100 plf on both

GENERAL CASER1R2R3wL1L2THIS RUNR1R2R3100 plf16 ft12 ftShear Vmax |V| = 954 lbVmaxMoment Mmax |M| = 2,600 lb·ftMx1M1

Formula set

  • M1 = −(wL23 + wL13)/8(L1 + L2)
  • R1 = V1 = M1/L1 + wL1/2
  • R2 = wL1 + wL2 − R1 − R3
  • R3 = V4 = M1/L2 + wL2/2
  • V2 = wL1 − R1;  V3 = wL2 − R3
  • Mx1 (at x1 = R1/w) = R1x1 − wx12/2
  • Mx2 (at x2 = R3/w) = R3x2 − wx22/2
QuantityGoverning formulaClosed formStructSuite engineDiff
R1M1/L1 + wL1/2637.5 lb637.5 lb0.00%
R2wL1 + wL2 − R1 − R31,779.2 lb1,779.2 lb0.00%
R3M1/L2 + wL2/2383.3 lb383.3 lb0.00%
VmaxV2 = wL1 − R1962.5 lb962.5 lb0.00%
M1 (at R2)(wL23 + wL13)/8(L1 + L2)2,600.0 lb·ft2,599.8 lb·ft0.01%
Mx1 (in span 1)R1x1 − wx12/22,032.0 lb·ft2,032.2 lb·ft0.01%

Figure 32 — Continuous Beam — Two Unequal Spans — Concentrated Load on Each Span Symmetrically Placed

This run: spans L1 = 16 ft and L2 = 12 ft, P1 = P2 = 1,000 lb at each span center

GENERAL CASER1R2R3P1P2aabbL1L2THIS RUNR1R2R31,000 lb1,000 lb8 ft8 ft6 ft6 ft16 ft12 ftShear Vmax |V| = 723 lbVmaxMoment Mmax |M| = 2,679 lb·ftMm1M1

Formula set

  • M1 = −(3/16)·(P1L12 + P2L22)/(L1 + L2)
  • R1 = M1/L1 + P1/2
  • R2 = P1 + P2 − R1 − R3
  • R3 = M1/L2 + P2/2
  • V1 = R1;  V2 = P1 − R1;  V3 = P2 − R3;  V4 = R3
  • Mm1 (at P1) = R1a
  • Mm2 (at P2) = R3b
QuantityGoverning formulaClosed formStructSuite engineDiff
R1M1/L1 + P1/2332.6 lb332.6 lb0.00%
R2P1 + P2 − R1 − R31,390.6 lb1,390.6 lb0.00%
R3M1/L2 + P2/2276.8 lb276.8 lb0.00%
VmaxV3 = P2 − R3723.2 lb723.2 lb0.00%
M1 (at R2)(3/16)(P1L12 + P2L22)/(L1 + L2)2,678.6 lb·ft2,678.6 lb·ft0.00%
Mm1 (at P1)R1a2,660.7 lb·ft2,660.7 lb·ft0.00%

Summary of results — one beam, every condition

All values below are the engine's, for the identical inputs above (Δmax is the largest deflection anywhere on the member, overhang tips included).

Fig.CaseM⁺max (lb·ft)M⁻max (lb·ft)Vmax (lb)Δmax (in)
Simple beams
1Uniformly Distributed Load3,2008000.399
2Uniform Load Partially Distributed2,4004000.285
3Uniform Load Partially Distributed at One End1,8006000.201
4Uniform Load Partially Distributed at Each End8004000.115
5Load Increasing Uniformly to One End1,6425330.200
6Load Increasing Uniformly to Center2,1344000.256
7Concentrated Load at Center4,0005000.399
8Concentrated Load at Any Point3,0007500.279
9Two Equal Concentrated Loads Symmetrically Placed4,0001,0000.549
10Two Equal Concentrated Loads Unsymmetrically Placed5,2501,1250.640
11Two Unequal Concentrated Loads Unsymmetrically Placed3,7509380.458
Cantilever beams
12Uniformly Distributed Load12,8001,6003.833
13Concentrated Load at Free End16,0001,0006.389
14Concentrated Load at Any Point12,0001,0004.043
Propped cantilevers (fixed at one end, supported at the other)
15Uniformly Distributed Load1,8003,2001,0000.166
16Concentrated Load at Center2,5003,0006880.179
17Concentrated Load at Any Point2,5311,8756330.153
Overhanging beams
18Uniformly Distributed Load2,8138008500.340
19Uniformly Distributed Load on Overhang8004000.095
20Concentrated Load at End of Overhang4,0001,0000.499
21Concentrated Load at Any Point Between Supports3,0007500.279
22Uniformly Distributed Load2,7078008380.325
Fixed-fixed beams
23Uniformly Distributed Load1,0672,1338000.080
24Concentrated Load at Center2,0002,0005000.100
25Concentrated Load at Any Point1,1252,2508440.054
Two-span continuous beams
26Uniform Load on One Span2,4501,6009000.281
27Concentrated Load at Center of One Span3,2501,5005940.288
28Concentrated Load at Any Point2,7669386910.214
29Uniformly Distributed Load1,8003,2001,0000.166
30Two Equal Concentrated Loads Symmetrically Placed2,5003,0006880.179
31Uniformly Distributed Load2,0322,6009620.208
32Concentrated Load on Each Span Symmetrically Placed2,6612,6797230.202

Four comparisons worth internalizing:

  • Support conditions are worth more than section size. The same 100 plf produces Mmax = 12,800 lb·ft as a cantilever, 3,200 lb·ft simply supported, and 2,133 lb·ft with both ends fixed — a 6.0:1 spread with identical load and length. No practical section upgrade moves capacity that far.
  • Deflection is even more dramatic. Under the uniform load the cantilever moves 3.83 in where the simple span moves 0.40 in and the fixed-fixed beam only 0.080 in — a 48× range. For the midspan point load the cantilever-to-simple ratio is 16× (6.39 in vs 0.399 in).
  • Continuity concentrates load on the middle support. With both 16-ft spans loaded, the center support carries R2 = 2,000 lb — 10/8 of wL, and 25% more than the 1,600-lb total a simple span would deliver to EACH of two separate posts. The post, plate crushing, and footing under R2 are designed by this number, not by wL/2.
  • Partial loading can pull a support DOWN. Load only one span of a continuous beam (Figure 26) and the far reaction is R3 = -100 lb — negative. The same happens loading only an overhang (Figure 19). Pattern loading isn't an academic refinement; it changes the sign of real connections.

Practical pitfalls when using these formulas

  • Units eat more designs than statics does. The deflection formulas want consistent units: with w in lb/in, L in inches, E in psi and I in in4, Δ comes out in inches. Feed L in feet into wL⁴/8EI and the answer is off by 12⁴ ≈ 21,000×. This page evaluates everything in inches and pounds, then reports M in lb·ft — do the same, in one direction, once.
  • Superposition is legal only while everything stays linear-elastic on the SAME structure. You may add Figure 1 + Figure 7 on the same simple span; you may not add a simple-span case to a fixed-end case, and you may not superpose onto a beam whose supports have changed (a prop added later is a different structure).
  • "Fixed" in the table means a real moment connection. A stud wall top plate or a couple of toe-nails is a pin, whatever the framing looks like. Use the fixed-end cases (Figures 27–32) only where the detail can actually develop M = wL²/12 — in wood construction that is rare enough to treat as the exception.
  • Pattern loading changes signs, not just magnitudes. Loading one span of the two-span beam (Figure 26) turns the far reaction NEGATIVE — a connection you sized for bearing now needs a tie-down. Any time a formula's reaction can go negative under partial load, detail for it.
  • The maximum is not always where you expect. For a load at "any point" (Figure 8), Mmax is under the load, not midspan; the deflection maximum sits at x = √(a(a + 2b)/3) (a > b) — near, but never at, the load. Read each formula's "at x = …" qualifier before you chase a midspan number.
  • These are analysis values, not designs. Nothing here contains CD, CM, CL or a single allowable stress. Take R/V/M/Δ from this page, then run the member through the Wood & Steel Beam module (or your own NDS/AISC checks) for capacity.

How these numbers are verified

Each case's closed-form values and the finite-element results above come from one shared definition file, evaluated by StructSuite's production beam engine (Hermite-element stiffness solution with consistent nodal loads — reactions are exact to machine precision for the true load positions, and shear is enveloped with support-face statics exactly as the design checks do). The automated test tests/verification/awc-da6-cases.test.ts re-runs all 32 cases on every build and fails if any quantity drifts. The check cuts both ways: a mistyped formula disagrees with the engine, and an engine regression disagrees with the formulas. The largest difference anywhere in the tables above is 0.20% — finite-element discretization at the app's own mesh, on quantities the closed forms give exactly.

Frequently Asked Questions

What is the formula for the maximum moment in a simply supported beam?

For a uniformly distributed load, Mmax = wL²/8 at midspan (Figure 1); for a concentrated load at midspan, Mmax = PL/4 (Figure 7); for a concentrated load at any point, Mmax = Pab/L under the load (Figure 8). On this page's 16-ft reference beam those give 3,200 lb·ft, 4,000 lb·ft, and 3,000 lb·ft respectively — each verified against the finite-element engine to within a small fraction of a percent.

What is the deflection formula for a cantilever beam?

Δmax = wL⁴/8EI at the free end for a uniform load (Figure 12), and Δmax = PL³/3EI for a point load at the tip (Figure 13). Note the contrast with the simple span (5wL⁴/384EI): for the same w, L, and EI the cantilever deflects 48/5 ≈ 9.6 times more — on this page's beam, 3.83 in versus 0.40 in.

Are these formulas ASD or LRFD?

Neither — they are statics. Reactions, shear, moment, and elastic deflection depend only on geometry, stiffness, and load, not on the design method. ASD vs LRFD enters afterwards, when factored (or unfactored) demands are compared to member capacities. That is also why one engine can serve both the NDS (ASD) wood checks and the AISC (LRFD) steel checks in the beam module: the analysis layer this page verifies is shared.

Why do the engine results differ from the formulas at all?

Because the engine is a finite-element solution: the beam is meshed into ~2-inch Hermite elements, moment is recovered element by element, and deflection is interpolated between nodes. Reactions come out exact to machine precision; moment and deflection carry discretization differences that stay in the hundredths of a percent at the app's mesh — the largest anywhere on this page is 0.20%. An agreement much tighter than engineering inputs are ever known to (loads are rarely known to 1%) — the point of the comparison is independence, not decimals.

Where do I get the original AWC Design Aid No. 6?

It's a free PDF from the American Wood Council: AWC DA6 — Beam Design Formulas with Shear and Moment Diagrams. Keep it in the truck; keep this page open next to your model. The figure numbers here match it one for one, so a reviewer can check either source against the other — and the resources directory collects it alongside the NDS, SDPWS, and the other documents a wood-design desk actually uses.

Build it in StructSuite

The same design, entered step by step in the module — with the practical judgment calls called out along the way.

  1. 1Step 1: Geometry & Configuration

    Design consideration

    This is AWC DA6 Figure 1 — the case every other beam condition is measured against. Simple span: Mmax = wL²/8 at midspan, R = V = wL/2 at each support. Pinned at both ends means no end restraint: all load resolves into vertical reactions and the moment diagram is a parabola returning to zero at the supports. Compare the same beam fixed at both ends (wL²/12 at the walls) or cantilevered (wL²/2) in the companion guide.

    In StructSuite

    Open Step 1: Geometry & Configuration. In the beam schematic, enter span lengths: 16. For each support, use the support type dropdown to select: Pinned, Pinned. A span is always the HORIZONTAL projection of the member. For a pitched member, switch on "Sloped member (rafter or pitched beam)" and enter the pitch either as "Roof slope (rise : run)" — any run, not just 12 — or as "Angle (degrees)"; the other boxes show the equivalent, and the figure that appears states the conversion factors. Leave the toggle off for a horizontal beam or joist. NDS 2024 Eq 3.3-1, 3.4-2 for flexure and shear.

  2. 2Step 2: Load Definition (ASCE 7-22 / NDS 2024)

    Design consideration

    One uniform 100 plf load, full span, self-weight OFF — the closed forms assume the entered load is the whole load, so excluding self-weight makes the hand check exact: total W = 100 × 16 = 1,600 lb, each reaction 800 lb, Mmax = 100 × 16²/8 = 3,200 lb-ft.

    In StructSuite

    Open the Loads section. Add load items with these exact values: D uniform 100 plf. For each load: set Type (D, L, Lr, S, W, E). Uniform loads take Input as — either "plf (lb/ft) directly" or "psf × tributary width" — and cover the whole beam unless you switch Extent to a start and end position. For a load whose intensity changes along the member, set the category to "Linearly varying (triangular or trapezoidal)" and enter w1 and w2 (a triangular load is simply w1 = 0). Point loads take magnitude (lb) and position (ft); applied moments take magnitude (lb·ft) and position (ft). Include self-weight. NDS 2024 Table 2.3.2 sets CD. If the beam has an end cantilever and the structure is assigned to SDC D–F, check the ASCE 7-22 §12.4.4 toggle to add the supplemental 0.14D net-uplift combination.

  3. 3Step 3: Material & Section

    Design consideration

    The 4x10 here is the analysis section of the formulas guide (E = 1.6×10⁶ psi, Ix = 230.8 in⁴ → Δmax = 5wL⁴/384EI = 0.40 in). The design side then applies the NDS adjustment factors (CF from Table 4A, CD for load duration) that the closed-form tables know nothing about — the difference between analysis and design.

    In StructSuite

    Open the Materials section. In Product category select the type; in Species select Douglas Fir-Larch; in Grade select No. 2; in Size select 4x10. Open Design Parameters: set Wet service (CM) to No; set Repetitive member to No; select Deflection limit. NDS 2024 §4.3.

Live design (pre-filled)

The form below is the real StructSuite module with this example's data loaded — every check recomputes from the current calculation engine on every visit, so the live results always reflect the latest module. Display only; values cannot be changed.

Wood beam — Design per 2024 NDS

National Design Specification for Wood Construction

This optional step is turned off. Check the box next to the step title to size a Simpson Strong-Tie hanger for the end reaction.

Where to go next